Gsyfuy

How to terminate ping <dest> &

Hacking a Safe Lock after 3 tries

Welcoming 2019 Pi day: How to draw the letter π?

Do these spellcasting foci from Xanathar's Guide to Everything have to be held in a hand?

Is it normal that my co-workers at a fitness company criticize my food choices?

Why do passenger jet manufacturers design their planes with stall prevention systems?

What did Alexander Pope mean by "Expletives their feeble Aid do join"?

Should we release the security issues we found in our product as CVE or we can just update those on weekly release notes?

Can I use USB data pins as power source

How to simplify this time periods definition interface?

compactness of a set where am I going wrong

Can a druid choose the size of its wild shape beast?

Did Ender ever learn that he killed Stilson and/or Bonzo?

Life insurance that covers only simultaneous/dual deaths

Does Mathematica reuse previous computations?

Are ETF trackers fundamentally better than individual stocks?

How do anti-virus programs start at Windows boot?

What is the significance behind "40 days" that often appears in the Bible?

Happy pi day, everyone!

My adviser wants to be the first author

How big is a MODIS 250m pixel in reality?

How to deal with taxi scam when on vacation?

Why did it take so long to abandon sail after steamships were demonstrated?

How to make healing in an exploration game interesting

What is the domain in a tikz parametric plot?

LaTeX equivalent of ConTeXt buffersHow can I put a coloured outline around fraction lines?How to define the default vertical distance between nodes?Numerical conditional within tikz keys?TikZ: Drawing an arc from an intersection to an intersectionHow to prevent rounded and duplicated tick labels in pgfplots with fixed precision?Drawing rectilinear curves in Tikz, aka an Etch-a-Sketch drawingLine up nested tikz enviroments or how to get rid of themHow to draw a square and its diagonals with arrows?Get tikz domain and range

2

I don't understand what's going on here. If the domain of the parametric parameter t is 0:100, then the function sin(2pi*t) should oscillate about 100 times, but it only oscillates a couple. What am I missing?

documentclass{article}

usepackage{tikz}

begin{document}

begin{tikzpicture}

  begin{scope}[x=.6textwidth,y=.6textwidth]

    draw[very thin,color=gray, step=.1] (0.0,0.0) grid (1,1);

    draw [ thick,  domain=0:100, samples=40, smooth, variable=t] 

    plot ({t/100}, {sin(2*pi*t)*.5+.5});

  end{scope}

end{tikzpicture}

end{document}

tikz-pgf plot domain

share|improve this question

asked 4 hours ago

argentum2fargentum2f

1336

add a comment | 

2

I don't understand what's going on here. If the domain of the parametric parameter t is 0:100, then the function sin(2pi*t) should oscillate about 100 times, but it only oscillates a couple. What am I missing?

documentclass{article}

usepackage{tikz}

begin{document}

begin{tikzpicture}

  begin{scope}[x=.6textwidth,y=.6textwidth]

    draw[very thin,color=gray, step=.1] (0.0,0.0) grid (1,1);

    draw [ thick,  domain=0:100, samples=40, smooth, variable=t] 

    plot ({t/100}, {sin(2*pi*t)*.5+.5});

  end{scope}

end{tikzpicture}

end{document}

tikz-pgf plot domain

share|improve this question

asked 4 hours ago

argentum2fargentum2f

1336

add a comment | 

I don't understand what's going on here. If the domain of the parametric parameter t is 0:100, then the function sin(2pi*t) should oscillate about 100 times, but it only oscillates a couple. What am I missing?

documentclass{article}

usepackage{tikz}

begin{document}

begin{tikzpicture}

  begin{scope}[x=.6textwidth,y=.6textwidth]

    draw[very thin,color=gray, step=.1] (0.0,0.0) grid (1,1);

    draw [ thick,  domain=0:100, samples=40, smooth, variable=t] 

    plot ({t/100}, {sin(2*pi*t)*.5+.5});

  end{scope}

end{tikzpicture}

end{document}

tikz-pgf plot domain

share|improve this question

asked 4 hours ago

argentum2fargentum2f

1336

documentclass{article}

usepackage{tikz}

begin{document}

begin{tikzpicture}

  begin{scope}[x=.6textwidth,y=.6textwidth]

    draw[very thin,color=gray, step=.1] (0.0,0.0) grid (1,1);

    draw [ thick,  domain=0:100, samples=40, smooth, variable=t] 

    plot ({t/100}, {sin(2*pi*t)*.5+.5});

  end{scope}

end{tikzpicture}

end{document}

share|improve this question

asked 4 hours ago

argentum2fargentum2f

1336

share|improve this question

asked 4 hours ago

argentum2fargentum2f

1336

asked 4 hours ago

argentum2fargentum2f

1336

asked 4 hours ago

argentum2fargentum2f

1336

1 Answer
1

active

oldest

votes

4

You got the domain right. The problem is that the trigonometric functions in TikZ are (oddly, in my opinion) in degrees by default. So 2*pi*t with t between 0 and 100 will give you the sine function (in degrees) between 0 and 628.3 degrees (which is about 10.96 radians) which almost 1.75 periods of the function. This is exactly what you see there: one full period and 3/4 of another.

You can tell TikZ to use radians by appending an r to the argument or using the rad function (see page 1005 of the TikZ-PGF manual, section 93.3.4 “Trigonometric functions”). I also added the FPU to allow the domain up to 100 and increased the number of samples to 400 following Kpym's suggestion (notice the aliasing):

documentclass{article}

usepackage{tikz}

usetikzlibrary{fpu}

begin{document}

begin{tikzpicture}

  begin{scope}[x=.6textwidth,y=.6textwidth]

    pgfkeys{/pgf/fpu=true,/pgf/fpu/output format=fixed}

    draw[very thin,color=gray, step=.1] (0.0,0.0) grid (1,1);

    draw [ thick,  domain=0:100, samples=400, smooth, variable=t]

    plot ({t/100}, {sin(2*pi*t r)*.5+.5});

  end{scope}%                   ^

end{tikzpicture}

end{document}

share|improve this answer

edited 4 hours ago

answered 4 hours ago

Phelype OleinikPhelype Oleinik

24.2k54688

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  with samples=400,smooth it looks better, but this is not the question ;)
  
  – Kpym
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Kpym Certainly! I just removed the smooth to show that 100 cycles with 40 samples won't do (unless OP wants to show the aliasing). Thanks anyway :)
  
  – Phelype Oleinik
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Doh! Degrees... Yeah, don't know why that didn't occur to me. I'm just so used to thinking in radians. Usually trigonometric functions are defined assuming radians, but I guess it makes sense since everywhere else in latex assumes angles are degrees. I actually did try and turn up the samples at first - thought it was just aliasing.
  
  – argentum2f
  3 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @argentum2f Yes, as I said “oddly”. All programming languages I know (which aren't that many, but...) have a sin function for argument radians and sind function for argument in degrees. Anyhow, Till must have had his reasons :)
  
  – Phelype Oleinik
  3 hours ago
  

  
  
  
  

add a comment | 

Your Answer

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "85"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Sign up using Google

Sign up using Facebook

Sign up using Email and Password

Post as a guest

Name

Email

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f479719%2fwhat-is-the-domain-in-a-tikz-parametric-plot%23new-answer', 'question_page');
}
);

Post as a guest

Name

Email

Required, but never shown

4

You got the domain right. The problem is that the trigonometric functions in TikZ are (oddly, in my opinion) in degrees by default. So 2*pi*t with t between 0 and 100 will give you the sine function (in degrees) between 0 and 628.3 degrees (which is about 10.96 radians) which almost 1.75 periods of the function. This is exactly what you see there: one full period and 3/4 of another.

You can tell TikZ to use radians by appending an r to the argument or using the rad function (see page 1005 of the TikZ-PGF manual, section 93.3.4 “Trigonometric functions”). I also added the FPU to allow the domain up to 100 and increased the number of samples to 400 following Kpym's suggestion (notice the aliasing):

documentclass{article}

usepackage{tikz}

usetikzlibrary{fpu}

begin{document}

begin{tikzpicture}

  begin{scope}[x=.6textwidth,y=.6textwidth]

    pgfkeys{/pgf/fpu=true,/pgf/fpu/output format=fixed}

    draw[very thin,color=gray, step=.1] (0.0,0.0) grid (1,1);

    draw [ thick,  domain=0:100, samples=400, smooth, variable=t]

    plot ({t/100}, {sin(2*pi*t r)*.5+.5});

  end{scope}%                   ^

end{tikzpicture}

end{document}

share|improve this answer

edited 4 hours ago

answered 4 hours ago

Phelype OleinikPhelype Oleinik

24.2k54688

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  with samples=400,smooth it looks better, but this is not the question ;)
  
  – Kpym
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Kpym Certainly! I just removed the smooth to show that 100 cycles with 40 samples won't do (unless OP wants to show the aliasing). Thanks anyway :)
  
  – Phelype Oleinik
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Doh! Degrees... Yeah, don't know why that didn't occur to me. I'm just so used to thinking in radians. Usually trigonometric functions are defined assuming radians, but I guess it makes sense since everywhere else in latex assumes angles are degrees. I actually did try and turn up the samples at first - thought it was just aliasing.
  
  – argentum2f
  3 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @argentum2f Yes, as I said “oddly”. All programming languages I know (which aren't that many, but...) have a sin function for argument radians and sind function for argument in degrees. Anyhow, Till must have had his reasons :)
  
  – Phelype Oleinik
  3 hours ago
  

  
  
  
  

add a comment | 

4

You got the domain right. The problem is that the trigonometric functions in TikZ are (oddly, in my opinion) in degrees by default. So 2*pi*t with t between 0 and 100 will give you the sine function (in degrees) between 0 and 628.3 degrees (which is about 10.96 radians) which almost 1.75 periods of the function. This is exactly what you see there: one full period and 3/4 of another.

You can tell TikZ to use radians by appending an r to the argument or using the rad function (see page 1005 of the TikZ-PGF manual, section 93.3.4 “Trigonometric functions”). I also added the FPU to allow the domain up to 100 and increased the number of samples to 400 following Kpym's suggestion (notice the aliasing):

documentclass{article}

usepackage{tikz}

usetikzlibrary{fpu}

begin{document}

begin{tikzpicture}

  begin{scope}[x=.6textwidth,y=.6textwidth]

    pgfkeys{/pgf/fpu=true,/pgf/fpu/output format=fixed}

    draw[very thin,color=gray, step=.1] (0.0,0.0) grid (1,1);

    draw [ thick,  domain=0:100, samples=400, smooth, variable=t]

    plot ({t/100}, {sin(2*pi*t r)*.5+.5});

  end{scope}%                   ^

end{tikzpicture}

end{document}

share|improve this answer

edited 4 hours ago

answered 4 hours ago

Phelype OleinikPhelype Oleinik

24.2k54688

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  with samples=400,smooth it looks better, but this is not the question ;)
  
  – Kpym
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Kpym Certainly! I just removed the smooth to show that 100 cycles with 40 samples won't do (unless OP wants to show the aliasing). Thanks anyway :)
  
  – Phelype Oleinik
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Doh! Degrees... Yeah, don't know why that didn't occur to me. I'm just so used to thinking in radians. Usually trigonometric functions are defined assuming radians, but I guess it makes sense since everywhere else in latex assumes angles are degrees. I actually did try and turn up the samples at first - thought it was just aliasing.
  
  – argentum2f
  3 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @argentum2f Yes, as I said “oddly”. All programming languages I know (which aren't that many, but...) have a sin function for argument radians and sind function for argument in degrees. Anyhow, Till must have had his reasons :)
  
  – Phelype Oleinik
  3 hours ago
  

  
  
  
  

add a comment | 

You got the domain right. The problem is that the trigonometric functions in TikZ are (oddly, in my opinion) in degrees by default. So 2*pi*t with t between 0 and 100 will give you the sine function (in degrees) between 0 and 628.3 degrees (which is about 10.96 radians) which almost 1.75 periods of the function. This is exactly what you see there: one full period and 3/4 of another.

You can tell TikZ to use radians by appending an r to the argument or using the rad function (see page 1005 of the TikZ-PGF manual, section 93.3.4 “Trigonometric functions”). I also added the FPU to allow the domain up to 100 and increased the number of samples to 400 following Kpym's suggestion (notice the aliasing):

documentclass{article}

usepackage{tikz}

usetikzlibrary{fpu}

begin{document}

begin{tikzpicture}

  begin{scope}[x=.6textwidth,y=.6textwidth]

    pgfkeys{/pgf/fpu=true,/pgf/fpu/output format=fixed}

    draw[very thin,color=gray, step=.1] (0.0,0.0) grid (1,1);

    draw [ thick,  domain=0:100, samples=400, smooth, variable=t]

    plot ({t/100}, {sin(2*pi*t r)*.5+.5});

  end{scope}%                   ^

end{tikzpicture}

end{document}

share|improve this answer

edited 4 hours ago

answered 4 hours ago

Phelype OleinikPhelype Oleinik

24.2k54688

documentclass{article}

usepackage{tikz}

usetikzlibrary{fpu}

begin{document}

begin{tikzpicture}

  begin{scope}[x=.6textwidth,y=.6textwidth]

    pgfkeys{/pgf/fpu=true,/pgf/fpu/output format=fixed}

    draw[very thin,color=gray, step=.1] (0.0,0.0) grid (1,1);

    draw [ thick,  domain=0:100, samples=400, smooth, variable=t]

    plot ({t/100}, {sin(2*pi*t r)*.5+.5});

  end{scope}%                   ^

end{tikzpicture}

end{document}

share|improve this answer

edited 4 hours ago

answered 4 hours ago

Phelype OleinikPhelype Oleinik

24.2k54688

answered 4 hours ago

Phelype OleinikPhelype Oleinik

24.2k54688

answered 4 hours ago

Phelype OleinikPhelype Oleinik

24.2k54688