QGIS: use geometry from different layer in symbology expressionCopying Symbology between layers with...
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QGIS: use geometry from different layer in symbology expression
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I have a project with multiple layers.
The purple dots are from a pointfile with the symbology-expression:
z($geometry)> '14.5'. (so it only displays a purple dot when the Z-value is more than 14.5m).
I have a second layer with polygons, visible as the partly-transparent arc-area in red.
The next step i want to make in my project is to:
have the purple dots appear only if:
z($geometry)>'14.5' AND
the x-y of that spot is within the geographical extent of the polygon from the second layer
What step do i have to take to get this done.
qgis symbology z-value
edited 3 hours ago
Matthias Kuhn
18.9k14890
asked 3 hours ago
CaptainAhabCaptainAhab
656
add a comment |
I have a project with multiple layers.
The purple dots are from a pointfile with the symbology-expression:
z($geometry)> '14.5'. (so it only displays a purple dot when the Z-value is more than 14.5m).
I have a second layer with polygons, visible as the partly-transparent arc-area in red.
The next step i want to make in my project is to:
have the purple dots appear only if:
z($geometry)>'14.5' AND
the x-y of that spot is within the geographical extent of the polygon from the second layer
What step do i have to take to get this done.
qgis symbology z-value
edited 3 hours ago
Matthias Kuhn
18.9k14890
asked 3 hours ago
CaptainAhabCaptainAhab
656
add a comment |
I have a project with multiple layers.
The purple dots are from a pointfile with the symbology-expression:
z($geometry)> '14.5'. (so it only displays a purple dot when the Z-value is more than 14.5m).
I have a second layer with polygons, visible as the partly-transparent arc-area in red.
The next step i want to make in my project is to:
have the purple dots appear only if:
z($geometry)>'14.5' AND
the x-y of that spot is within the geographical extent of the polygon from the second layer
What step do i have to take to get this done.
qgis symbology z-value
edited 3 hours ago
Matthias Kuhn
18.9k14890
asked 3 hours ago
CaptainAhabCaptainAhab
656
I have a project with multiple layers.
The purple dots are from a pointfile with the symbology-expression:
z($geometry)> '14.5'. (so it only displays a purple dot when the Z-value is more than 14.5m).
I have a second layer with polygons, visible as the partly-transparent arc-area in red.
The next step i want to make in my project is to:
have the purple dots appear only if:
z($geometry)>'14.5' AND
the x-y of that spot is within the geographical extent of the polygon from the second layer
What step do i have to take to get this done.
qgis symbology z-value
qgis symbology z-value
edited 3 hours ago
Matthias Kuhn
18.9k14890
asked 3 hours ago
CaptainAhabCaptainAhab
656
edited 3 hours ago
Matthias Kuhn
18.9k14890
asked 3 hours ago
CaptainAhabCaptainAhab
656
edited 3 hours ago
Matthias Kuhn
18.9k14890
edited 3 hours ago
Matthias Kuhn
18.9k14890
edited 3 hours ago
Matthias Kuhn
18.9k14890
18.9k14890
asked 3 hours ago
CaptainAhabCaptainAhab
656
asked 3 hours ago
CaptainAhabCaptainAhab
656
asked 3 hours ago
CaptainAhabCaptainAhab
656
656
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Your question is very similar to what I've done here recently.
I used expression:
if(
within($geometry,geometry(get_feature(layer,attribute,value))),
result_when_true,
result_when_false
)
In your case step 1: filter data table by
z($geometry)> '14.5'
step 2: paste expression in point symbology layer (see gif to find where)
if(
within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
1,
0
)
You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.
That's it.
answered 2 hours ago
VitruviusVitruvius
429210
Good answer! Would it work to drop the if-part completely and just usewithin(...)?
– Matthias Kuhn
50 mins ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your question is very similar to what I've done here recently.
I used expression:
if(
within($geometry,geometry(get_feature(layer,attribute,value))),
result_when_true,
result_when_false
)
In your case step 1: filter data table by
z($geometry)> '14.5'
step 2: paste expression in point symbology layer (see gif to find where)
if(
within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
1,
0
)
You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.
That's it.
answered 2 hours ago
VitruviusVitruvius
429210
Good answer! Would it work to drop the if-part completely and just usewithin(...)?
– Matthias Kuhn
50 mins ago
add a comment |
Your question is very similar to what I've done here recently.
I used expression:
if(
within($geometry,geometry(get_feature(layer,attribute,value))),
result_when_true,
result_when_false
)
In your case step 1: filter data table by
z($geometry)> '14.5'
step 2: paste expression in point symbology layer (see gif to find where)
if(
within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
1,
0
)
You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.
That's it.
answered 2 hours ago
VitruviusVitruvius
429210
Good answer! Would it work to drop the if-part completely and just usewithin(...)?
– Matthias Kuhn
50 mins ago
add a comment |
Your question is very similar to what I've done here recently.
I used expression:
if(
within($geometry,geometry(get_feature(layer,attribute,value))),
result_when_true,
result_when_false
)
In your case step 1: filter data table by
z($geometry)> '14.5'
step 2: paste expression in point symbology layer (see gif to find where)
if(
within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
1,
0
)
You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.
That's it.
answered 2 hours ago
VitruviusVitruvius
429210
Your question is very similar to what I've done here recently.
I used expression:
if(
within($geometry,geometry(get_feature(layer,attribute,value))),
result_when_true,
result_when_false
)
In your case step 1: filter data table by
z($geometry)> '14.5'
step 2: paste expression in point symbology layer (see gif to find where)
if(
within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
1,
0
)
You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.
That's it.
answered 2 hours ago
VitruviusVitruvius
429210
edited 1 hour ago
answered 2 hours ago
VitruviusVitruvius
429210
answered 2 hours ago
VitruviusVitruvius
429210
answered 2 hours ago
VitruviusVitruvius
429210
429210
Good answer! Would it work to drop the if-part completely and just usewithin(...)?
– Matthias Kuhn
50 mins ago
add a comment |
Good answer! Would it work to drop the if-part completely and just usewithin(...)?
– Matthias Kuhn
50 mins ago
Good answer! Would it work to drop the if-part completely and just use
within(...)?– Matthias Kuhn
50 mins ago
Good answer! Would it work to drop the if-part completely and just use
within(...)?– Matthias Kuhn
50 mins ago
add a comment |
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