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Dynamic filling of a region of a polar plot



Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
Announcing the arrival of Valued Associate #679: Cesar Manara
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3












$begingroup$


I would like to shade area of region as a function of angle using PolarPlot.
Here is my attempt.



With[
{pts =
Cases[PolarPlot[1 + 2 Sin[θ], {θ, 0, 2 π}], _Line, {0, Infinity}][[1, 1]]},
Manipulate[
Show[
ListLinePlot[{{{0, 0}, pts[[n]]}, pts[[1 ;; n]]},
Filling -> {2 -> {Axis, LightBlue}, 1 -> {Axis, LightBlue}},
PlotRange -> {{-2, 2}, {-0.5, 3.2}}, AspectRatio -> 1,
PlotStyle -> Directive[AbsoluteThickness@3, Magenta, Magenta],
ImageSize -> 500, AxesStyle -> Directive[Black, 18],
PlotLabel -> Style["r=1+2 sin(θ)", Black, 20]],
PolarPlot[1 + 2 Sin[θ], {θ, 0, 2.2 π},
AspectRatio -> 1, PlotStyle -> {Black, AbsoluteThickness@3}]],
{n, 1, Length @ pts, 1}]]


enter image description here



enter image description here



Two thing I would like to achieve:




  1. I don't want to see the yellow highlited region.

  2. When inner loop is shaded twice, I would like to make it darker to emphasize that it is the 2nd time.


Any suggestion..










share|improve this question











$endgroup$

















    3












    $begingroup$


    I would like to shade area of region as a function of angle using PolarPlot.
    Here is my attempt.



    With[
    {pts =
    Cases[PolarPlot[1 + 2 Sin[θ], {θ, 0, 2 π}], _Line, {0, Infinity}][[1, 1]]},
    Manipulate[
    Show[
    ListLinePlot[{{{0, 0}, pts[[n]]}, pts[[1 ;; n]]},
    Filling -> {2 -> {Axis, LightBlue}, 1 -> {Axis, LightBlue}},
    PlotRange -> {{-2, 2}, {-0.5, 3.2}}, AspectRatio -> 1,
    PlotStyle -> Directive[AbsoluteThickness@3, Magenta, Magenta],
    ImageSize -> 500, AxesStyle -> Directive[Black, 18],
    PlotLabel -> Style["r=1+2 sin(θ)", Black, 20]],
    PolarPlot[1 + 2 Sin[θ], {θ, 0, 2.2 π},
    AspectRatio -> 1, PlotStyle -> {Black, AbsoluteThickness@3}]],
    {n, 1, Length @ pts, 1}]]


    enter image description here



    enter image description here



    Two thing I would like to achieve:




    1. I don't want to see the yellow highlited region.

    2. When inner loop is shaded twice, I would like to make it darker to emphasize that it is the 2nd time.


    Any suggestion..










    share|improve this question











    $endgroup$















      3












      3








      3





      $begingroup$


      I would like to shade area of region as a function of angle using PolarPlot.
      Here is my attempt.



      With[
      {pts =
      Cases[PolarPlot[1 + 2 Sin[θ], {θ, 0, 2 π}], _Line, {0, Infinity}][[1, 1]]},
      Manipulate[
      Show[
      ListLinePlot[{{{0, 0}, pts[[n]]}, pts[[1 ;; n]]},
      Filling -> {2 -> {Axis, LightBlue}, 1 -> {Axis, LightBlue}},
      PlotRange -> {{-2, 2}, {-0.5, 3.2}}, AspectRatio -> 1,
      PlotStyle -> Directive[AbsoluteThickness@3, Magenta, Magenta],
      ImageSize -> 500, AxesStyle -> Directive[Black, 18],
      PlotLabel -> Style["r=1+2 sin(θ)", Black, 20]],
      PolarPlot[1 + 2 Sin[θ], {θ, 0, 2.2 π},
      AspectRatio -> 1, PlotStyle -> {Black, AbsoluteThickness@3}]],
      {n, 1, Length @ pts, 1}]]


      enter image description here



      enter image description here



      Two thing I would like to achieve:




      1. I don't want to see the yellow highlited region.

      2. When inner loop is shaded twice, I would like to make it darker to emphasize that it is the 2nd time.


      Any suggestion..










      share|improve this question











      $endgroup$




      I would like to shade area of region as a function of angle using PolarPlot.
      Here is my attempt.



      With[
      {pts =
      Cases[PolarPlot[1 + 2 Sin[θ], {θ, 0, 2 π}], _Line, {0, Infinity}][[1, 1]]},
      Manipulate[
      Show[
      ListLinePlot[{{{0, 0}, pts[[n]]}, pts[[1 ;; n]]},
      Filling -> {2 -> {Axis, LightBlue}, 1 -> {Axis, LightBlue}},
      PlotRange -> {{-2, 2}, {-0.5, 3.2}}, AspectRatio -> 1,
      PlotStyle -> Directive[AbsoluteThickness@3, Magenta, Magenta],
      ImageSize -> 500, AxesStyle -> Directive[Black, 18],
      PlotLabel -> Style["r=1+2 sin(θ)", Black, 20]],
      PolarPlot[1 + 2 Sin[θ], {θ, 0, 2.2 π},
      AspectRatio -> 1, PlotStyle -> {Black, AbsoluteThickness@3}]],
      {n, 1, Length @ pts, 1}]]


      enter image description here



      enter image description here



      Two thing I would like to achieve:




      1. I don't want to see the yellow highlited region.

      2. When inner loop is shaded twice, I would like to make it darker to emphasize that it is the 2nd time.


      Any suggestion..







      plotting filling






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 1 hour ago







      Okkes Dulgerci

















      asked 3 hours ago









      Okkes DulgerciOkkes Dulgerci

      5,4641919




      5,4641919






















          1 Answer
          1






          active

          oldest

          votes


















          2












          $begingroup$

          This is what you need:



          Manipulate[ParametricPlot[
          r (1 + 2 Sin[θ]) {Cos[θ], Sin[θ]},
          {θ, 0, thmax},
          {r, 0, 1},
          PlotRange -> {{-2.25, 2.25}, {-0.5, 3.5}},
          PerformanceGoal -> "Quality"
          ], {thmax, 0.01, 2 Pi}]


          Mathematica graphics






          share|improve this answer











          $endgroup$














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            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            2












            $begingroup$

            This is what you need:



            Manipulate[ParametricPlot[
            r (1 + 2 Sin[θ]) {Cos[θ], Sin[θ]},
            {θ, 0, thmax},
            {r, 0, 1},
            PlotRange -> {{-2.25, 2.25}, {-0.5, 3.5}},
            PerformanceGoal -> "Quality"
            ], {thmax, 0.01, 2 Pi}]


            Mathematica graphics






            share|improve this answer











            $endgroup$


















              2












              $begingroup$

              This is what you need:



              Manipulate[ParametricPlot[
              r (1 + 2 Sin[θ]) {Cos[θ], Sin[θ]},
              {θ, 0, thmax},
              {r, 0, 1},
              PlotRange -> {{-2.25, 2.25}, {-0.5, 3.5}},
              PerformanceGoal -> "Quality"
              ], {thmax, 0.01, 2 Pi}]


              Mathematica graphics






              share|improve this answer











              $endgroup$
















                2












                2








                2





                $begingroup$

                This is what you need:



                Manipulate[ParametricPlot[
                r (1 + 2 Sin[θ]) {Cos[θ], Sin[θ]},
                {θ, 0, thmax},
                {r, 0, 1},
                PlotRange -> {{-2.25, 2.25}, {-0.5, 3.5}},
                PerformanceGoal -> "Quality"
                ], {thmax, 0.01, 2 Pi}]


                Mathematica graphics






                share|improve this answer











                $endgroup$



                This is what you need:



                Manipulate[ParametricPlot[
                r (1 + 2 Sin[θ]) {Cos[θ], Sin[θ]},
                {θ, 0, thmax},
                {r, 0, 1},
                PlotRange -> {{-2.25, 2.25}, {-0.5, 3.5}},
                PerformanceGoal -> "Quality"
                ], {thmax, 0.01, 2 Pi}]


                Mathematica graphics







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 45 mins ago









                m_goldberg

                88.9k873200




                88.9k873200










                answered 1 hour ago









                C. E.C. E.

                51.2k3101207




                51.2k3101207






























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