How to Fetch results from server using JQuery AJAX? on the basis of Drop-down ConditionHow to structure Ajax...

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How to Fetch results from server using JQuery AJAX? on the basis of Drop-down Condition


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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}







0















I have two conditions, if two conditions are matching the given value should display. I am using input value as Drop down. If the value of two drop-downs matched i need to display my value on same page.
For Example:
dropDown1 selection -> KM : 10(Dropdown),
dropDown1 selection -> Fueal : 2 Lit(Dropdown)



Output: Happy Jorney
On the same page and below the drop-down List.










share|improve this question

























  • if you need a condition within ajax functionality (or) before ajax functionality

    – divya sekar
    1 hour ago











  • @divyasekar If two drop-down select and if it is matching the value should be display below like i.stack.imgur.com/Kg9pA.png

    – zus
    1 hour ago











  • You are are confusing using word Ajax. its on page JS give me few minutes I will let you know.

    – Hassan Ali Shahzad
    1 hour ago











  • @HassanAliShahzad Let me explain, i need the the value should be display without click or refresh the page, so that i need AJAX,

    – zus
    1 hour ago











  • ok now its second part after selection from where you will get result ? on the basis of two matched sections.

    – Hassan Ali Shahzad
    1 hour ago




















0















I have two conditions, if two conditions are matching the given value should display. I am using input value as Drop down. If the value of two drop-downs matched i need to display my value on same page.
For Example:
dropDown1 selection -> KM : 10(Dropdown),
dropDown1 selection -> Fueal : 2 Lit(Dropdown)



Output: Happy Jorney
On the same page and below the drop-down List.










share|improve this question

























  • if you need a condition within ajax functionality (or) before ajax functionality

    – divya sekar
    1 hour ago











  • @divyasekar If two drop-down select and if it is matching the value should be display below like i.stack.imgur.com/Kg9pA.png

    – zus
    1 hour ago











  • You are are confusing using word Ajax. its on page JS give me few minutes I will let you know.

    – Hassan Ali Shahzad
    1 hour ago











  • @HassanAliShahzad Let me explain, i need the the value should be display without click or refresh the page, so that i need AJAX,

    – zus
    1 hour ago











  • ok now its second part after selection from where you will get result ? on the basis of two matched sections.

    – Hassan Ali Shahzad
    1 hour ago
















0












0








0








I have two conditions, if two conditions are matching the given value should display. I am using input value as Drop down. If the value of two drop-downs matched i need to display my value on same page.
For Example:
dropDown1 selection -> KM : 10(Dropdown),
dropDown1 selection -> Fueal : 2 Lit(Dropdown)



Output: Happy Jorney
On the same page and below the drop-down List.










share|improve this question
















I have two conditions, if two conditions are matching the given value should display. I am using input value as Drop down. If the value of two drop-downs matched i need to display my value on same page.
For Example:
dropDown1 selection -> KM : 10(Dropdown),
dropDown1 selection -> Fueal : 2 Lit(Dropdown)



Output: Happy Jorney
On the same page and below the drop-down List.







ajax php-7 dropdown-options






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 25 mins ago









Hassan Ali Shahzad

709317




709317










asked 1 hour ago









zuszus

87119




87119













  • if you need a condition within ajax functionality (or) before ajax functionality

    – divya sekar
    1 hour ago











  • @divyasekar If two drop-down select and if it is matching the value should be display below like i.stack.imgur.com/Kg9pA.png

    – zus
    1 hour ago











  • You are are confusing using word Ajax. its on page JS give me few minutes I will let you know.

    – Hassan Ali Shahzad
    1 hour ago











  • @HassanAliShahzad Let me explain, i need the the value should be display without click or refresh the page, so that i need AJAX,

    – zus
    1 hour ago











  • ok now its second part after selection from where you will get result ? on the basis of two matched sections.

    – Hassan Ali Shahzad
    1 hour ago





















  • if you need a condition within ajax functionality (or) before ajax functionality

    – divya sekar
    1 hour ago











  • @divyasekar If two drop-down select and if it is matching the value should be display below like i.stack.imgur.com/Kg9pA.png

    – zus
    1 hour ago











  • You are are confusing using word Ajax. its on page JS give me few minutes I will let you know.

    – Hassan Ali Shahzad
    1 hour ago











  • @HassanAliShahzad Let me explain, i need the the value should be display without click or refresh the page, so that i need AJAX,

    – zus
    1 hour ago











  • ok now its second part after selection from where you will get result ? on the basis of two matched sections.

    – Hassan Ali Shahzad
    1 hour ago



















if you need a condition within ajax functionality (or) before ajax functionality

– divya sekar
1 hour ago





if you need a condition within ajax functionality (or) before ajax functionality

– divya sekar
1 hour ago













@divyasekar If two drop-down select and if it is matching the value should be display below like i.stack.imgur.com/Kg9pA.png

– zus
1 hour ago





@divyasekar If two drop-down select and if it is matching the value should be display below like i.stack.imgur.com/Kg9pA.png

– zus
1 hour ago













You are are confusing using word Ajax. its on page JS give me few minutes I will let you know.

– Hassan Ali Shahzad
1 hour ago





You are are confusing using word Ajax. its on page JS give me few minutes I will let you know.

– Hassan Ali Shahzad
1 hour ago













@HassanAliShahzad Let me explain, i need the the value should be display without click or refresh the page, so that i need AJAX,

– zus
1 hour ago





@HassanAliShahzad Let me explain, i need the the value should be display without click or refresh the page, so that i need AJAX,

– zus
1 hour ago













ok now its second part after selection from where you will get result ? on the basis of two matched sections.

– Hassan Ali Shahzad
1 hour ago







ok now its second part after selection from where you will get result ? on the basis of two matched sections.

– Hassan Ali Shahzad
1 hour ago












1 Answer
1






active

oldest

votes


















1














For that you have two files basically, look the code your will get clear understanding for request flow also it will not change user selction:



your html file will be testing.html



<html>
<head>
<title> Upgrade Cost</title>
<script src="//ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script>
</head>

<form method='POST' action='home.php'>

Name : <input type="text" name="name"/><br/><br/>
Email Id : <input type="text" name="email_id"/><br/><br/>
Contact Number : <input type="text" name="contact_number"/><br/><br/>
I have :
<select id="old">
<option value = "select_option">Select Option</option>
<option value = "one">One</option>
<option value = "two">Two</option>
<option value = "three">Three</option>
<option value = "four">Four</option>
<option value = "five">Five</option>
</select><br/><br/>
I want :
<select id="new">
<option value = "select_option">Select Option</option>
<option value = "one">One</option>
<option value = "two">Two</option>
<option value = "three">Three</option>
<option value = "four">Four</option>
<option value = "five">Five</option>
</select>
</form>
<!-- <button id="btn_check_value">Check for value</button> -->
<div id="result"></div>
<script>
$(document).ready(function(){

$('#new').on('change',function(){

var old_val = $("#old option:selected").val();
var new_val = $("#new option:selected").val();
$.ajax({
type: "POST",
url: "home.php",
dataType: "text",
data: { old: old_val, new: new_val },
success: function(data) {
// Check the output of ajax call on firebug console
//console.log(data);
$('#result').html(data);
}
});

});
});

</script>
</html>


you ajax file will be:



<?php
if(isset($_POST['old']) && isset($_POST['new'])){
$old = $_POST['old'];
$new = $_POST['new'];
if($old=='one'&&$new=='two'){

// echo json_encode(array('Cost 10$'));
echo "Upgrade Code : 10$";
}

elseif($old=='one'&&$new=='three')
{
echo "Upgrade Code : 20$";
}

elseif($old=='one'&&$new=='four')
{
echo "Upgrade Code : 30$";
}


elseif($old=='one'&&$new=='five')
{
echo "Upgrade Code : 40$";
}
else{
echo "Choose Valid Options";;
}
}
?>





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    1 Answer
    1






    active

    oldest

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    active

    oldest

    votes






    active

    oldest

    votes









    1














    For that you have two files basically, look the code your will get clear understanding for request flow also it will not change user selction:



    your html file will be testing.html



    <html>
    <head>
    <title> Upgrade Cost</title>
    <script src="//ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script>
    </head>

    <form method='POST' action='home.php'>

    Name : <input type="text" name="name"/><br/><br/>
    Email Id : <input type="text" name="email_id"/><br/><br/>
    Contact Number : <input type="text" name="contact_number"/><br/><br/>
    I have :
    <select id="old">
    <option value = "select_option">Select Option</option>
    <option value = "one">One</option>
    <option value = "two">Two</option>
    <option value = "three">Three</option>
    <option value = "four">Four</option>
    <option value = "five">Five</option>
    </select><br/><br/>
    I want :
    <select id="new">
    <option value = "select_option">Select Option</option>
    <option value = "one">One</option>
    <option value = "two">Two</option>
    <option value = "three">Three</option>
    <option value = "four">Four</option>
    <option value = "five">Five</option>
    </select>
    </form>
    <!-- <button id="btn_check_value">Check for value</button> -->
    <div id="result"></div>
    <script>
    $(document).ready(function(){

    $('#new').on('change',function(){

    var old_val = $("#old option:selected").val();
    var new_val = $("#new option:selected").val();
    $.ajax({
    type: "POST",
    url: "home.php",
    dataType: "text",
    data: { old: old_val, new: new_val },
    success: function(data) {
    // Check the output of ajax call on firebug console
    //console.log(data);
    $('#result').html(data);
    }
    });

    });
    });

    </script>
    </html>


    you ajax file will be:



    <?php
    if(isset($_POST['old']) && isset($_POST['new'])){
    $old = $_POST['old'];
    $new = $_POST['new'];
    if($old=='one'&&$new=='two'){

    // echo json_encode(array('Cost 10$'));
    echo "Upgrade Code : 10$";
    }

    elseif($old=='one'&&$new=='three')
    {
    echo "Upgrade Code : 20$";
    }

    elseif($old=='one'&&$new=='four')
    {
    echo "Upgrade Code : 30$";
    }


    elseif($old=='one'&&$new=='five')
    {
    echo "Upgrade Code : 40$";
    }
    else{
    echo "Choose Valid Options";;
    }
    }
    ?>





    share|improve this answer




























      1














      For that you have two files basically, look the code your will get clear understanding for request flow also it will not change user selction:



      your html file will be testing.html



      <html>
      <head>
      <title> Upgrade Cost</title>
      <script src="//ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script>
      </head>

      <form method='POST' action='home.php'>

      Name : <input type="text" name="name"/><br/><br/>
      Email Id : <input type="text" name="email_id"/><br/><br/>
      Contact Number : <input type="text" name="contact_number"/><br/><br/>
      I have :
      <select id="old">
      <option value = "select_option">Select Option</option>
      <option value = "one">One</option>
      <option value = "two">Two</option>
      <option value = "three">Three</option>
      <option value = "four">Four</option>
      <option value = "five">Five</option>
      </select><br/><br/>
      I want :
      <select id="new">
      <option value = "select_option">Select Option</option>
      <option value = "one">One</option>
      <option value = "two">Two</option>
      <option value = "three">Three</option>
      <option value = "four">Four</option>
      <option value = "five">Five</option>
      </select>
      </form>
      <!-- <button id="btn_check_value">Check for value</button> -->
      <div id="result"></div>
      <script>
      $(document).ready(function(){

      $('#new').on('change',function(){

      var old_val = $("#old option:selected").val();
      var new_val = $("#new option:selected").val();
      $.ajax({
      type: "POST",
      url: "home.php",
      dataType: "text",
      data: { old: old_val, new: new_val },
      success: function(data) {
      // Check the output of ajax call on firebug console
      //console.log(data);
      $('#result').html(data);
      }
      });

      });
      });

      </script>
      </html>


      you ajax file will be:



      <?php
      if(isset($_POST['old']) && isset($_POST['new'])){
      $old = $_POST['old'];
      $new = $_POST['new'];
      if($old=='one'&&$new=='two'){

      // echo json_encode(array('Cost 10$'));
      echo "Upgrade Code : 10$";
      }

      elseif($old=='one'&&$new=='three')
      {
      echo "Upgrade Code : 20$";
      }

      elseif($old=='one'&&$new=='four')
      {
      echo "Upgrade Code : 30$";
      }


      elseif($old=='one'&&$new=='five')
      {
      echo "Upgrade Code : 40$";
      }
      else{
      echo "Choose Valid Options";;
      }
      }
      ?>





      share|improve this answer


























        1












        1








        1







        For that you have two files basically, look the code your will get clear understanding for request flow also it will not change user selction:



        your html file will be testing.html



        <html>
        <head>
        <title> Upgrade Cost</title>
        <script src="//ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script>
        </head>

        <form method='POST' action='home.php'>

        Name : <input type="text" name="name"/><br/><br/>
        Email Id : <input type="text" name="email_id"/><br/><br/>
        Contact Number : <input type="text" name="contact_number"/><br/><br/>
        I have :
        <select id="old">
        <option value = "select_option">Select Option</option>
        <option value = "one">One</option>
        <option value = "two">Two</option>
        <option value = "three">Three</option>
        <option value = "four">Four</option>
        <option value = "five">Five</option>
        </select><br/><br/>
        I want :
        <select id="new">
        <option value = "select_option">Select Option</option>
        <option value = "one">One</option>
        <option value = "two">Two</option>
        <option value = "three">Three</option>
        <option value = "four">Four</option>
        <option value = "five">Five</option>
        </select>
        </form>
        <!-- <button id="btn_check_value">Check for value</button> -->
        <div id="result"></div>
        <script>
        $(document).ready(function(){

        $('#new').on('change',function(){

        var old_val = $("#old option:selected").val();
        var new_val = $("#new option:selected").val();
        $.ajax({
        type: "POST",
        url: "home.php",
        dataType: "text",
        data: { old: old_val, new: new_val },
        success: function(data) {
        // Check the output of ajax call on firebug console
        //console.log(data);
        $('#result').html(data);
        }
        });

        });
        });

        </script>
        </html>


        you ajax file will be:



        <?php
        if(isset($_POST['old']) && isset($_POST['new'])){
        $old = $_POST['old'];
        $new = $_POST['new'];
        if($old=='one'&&$new=='two'){

        // echo json_encode(array('Cost 10$'));
        echo "Upgrade Code : 10$";
        }

        elseif($old=='one'&&$new=='three')
        {
        echo "Upgrade Code : 20$";
        }

        elseif($old=='one'&&$new=='four')
        {
        echo "Upgrade Code : 30$";
        }


        elseif($old=='one'&&$new=='five')
        {
        echo "Upgrade Code : 40$";
        }
        else{
        echo "Choose Valid Options";;
        }
        }
        ?>





        share|improve this answer













        For that you have two files basically, look the code your will get clear understanding for request flow also it will not change user selction:



        your html file will be testing.html



        <html>
        <head>
        <title> Upgrade Cost</title>
        <script src="//ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script>
        </head>

        <form method='POST' action='home.php'>

        Name : <input type="text" name="name"/><br/><br/>
        Email Id : <input type="text" name="email_id"/><br/><br/>
        Contact Number : <input type="text" name="contact_number"/><br/><br/>
        I have :
        <select id="old">
        <option value = "select_option">Select Option</option>
        <option value = "one">One</option>
        <option value = "two">Two</option>
        <option value = "three">Three</option>
        <option value = "four">Four</option>
        <option value = "five">Five</option>
        </select><br/><br/>
        I want :
        <select id="new">
        <option value = "select_option">Select Option</option>
        <option value = "one">One</option>
        <option value = "two">Two</option>
        <option value = "three">Three</option>
        <option value = "four">Four</option>
        <option value = "five">Five</option>
        </select>
        </form>
        <!-- <button id="btn_check_value">Check for value</button> -->
        <div id="result"></div>
        <script>
        $(document).ready(function(){

        $('#new').on('change',function(){

        var old_val = $("#old option:selected").val();
        var new_val = $("#new option:selected").val();
        $.ajax({
        type: "POST",
        url: "home.php",
        dataType: "text",
        data: { old: old_val, new: new_val },
        success: function(data) {
        // Check the output of ajax call on firebug console
        //console.log(data);
        $('#result').html(data);
        }
        });

        });
        });

        </script>
        </html>


        you ajax file will be:



        <?php
        if(isset($_POST['old']) && isset($_POST['new'])){
        $old = $_POST['old'];
        $new = $_POST['new'];
        if($old=='one'&&$new=='two'){

        // echo json_encode(array('Cost 10$'));
        echo "Upgrade Code : 10$";
        }

        elseif($old=='one'&&$new=='three')
        {
        echo "Upgrade Code : 20$";
        }

        elseif($old=='one'&&$new=='four')
        {
        echo "Upgrade Code : 30$";
        }


        elseif($old=='one'&&$new=='five')
        {
        echo "Upgrade Code : 40$";
        }
        else{
        echo "Choose Valid Options";;
        }
        }
        ?>






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 38 mins ago









        Hassan Ali ShahzadHassan Ali Shahzad

        709317




        709317






























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