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2

$begingroup$

Is it possible to use GraphicsGrid and do something like this?

$begin{array}{cccc}
text{X} & Label1 & Label2& Label3\
Label4 & Plot1 & Plot2&Plot3\
Label5 & Plot4 & Plot5&Plot6\
Label6 & Plot7 & Plot8&Plot9\
end{array} $

graphics visualization

share|improve this question

asked 4 hours ago

An old man in the sea.An old man in the sea.

1,079919

$endgroup$

add a comment | 

2

$begingroup$

Is it possible to use GraphicsGrid and do something like this?

$begin{array}{cccc}
text{X} & Label1 & Label2& Label3\
Label4 & Plot1 & Plot2&Plot3\
Label5 & Plot4 & Plot5&Plot6\
Label6 & Plot7 & Plot8&Plot9\
end{array} $

graphics visualization

share|improve this question

asked 4 hours ago

An old man in the sea.An old man in the sea.

1,079919

$endgroup$

add a comment | 

$begingroup$

Is it possible to use GraphicsGrid and do something like this?

$begin{array}{cccc}
text{X} & Label1 & Label2& Label3\
Label4 & Plot1 & Plot2&Plot3\
Label5 & Plot4 & Plot5&Plot6\
Label6 & Plot7 & Plot8&Plot9\
end{array} $

graphics visualization

share|improve this question

asked 4 hours ago

An old man in the sea.An old man in the sea.

1,079919

$endgroup$

share|improve this question

asked 4 hours ago

An old man in the sea.An old man in the sea.

1,079919

share|improve this question

asked 4 hours ago

An old man in the sea.An old man in the sea.

1,079919

asked 4 hours ago

An old man in the sea.An old man in the sea.

1,079919

asked 4 hours ago

An old man in the sea.An old man in the sea.

1,079919

3 Answers
3

active

oldest

votes

1

$begingroup$

Here is an option:

plots = Table[Table[Plot[Sin[i x + j], {x, 1, 10}], {i, 3}], {j, 3}];

xlabels = {"", "Label 1", "Label 2", "Label 3"};

ylabels = {"Label 4", "Label 5", "Label 6"};

GraphicsGrid[Join[{xlabels}, Transpose[Join[{ylabels}, Transpose[plots]]]]]

share|improve this answer

answered 2 hours ago

MelaGoMelaGo

4863

$endgroup$

add a comment | 

1

$begingroup$

You could construct Graphics for the row and column headings. Something like this. Would have to adjust the vertical / horizontal placement of the label text.

plotGrid = Table[Plot[Sin[x], {x, 0, 2 Pi}], 2, 2];



plotRowHeader = 

 Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 2}];



plotColumnHeader = 

  Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 3, 

     4}] // Prepend[Graphics[Style[Text["X"], 12]]];



graphicsGrid = 

  plotGrid // Prepend[plotRowHeader] // Transpose // 

   Prepend[plotColumnHeader];



GraphicsGrid[graphicsGrid]

share|improve this answer

answered 2 hours ago

Rohit NamjoshiRohit Namjoshi

1,4821213

$endgroup$

add a comment | 

1

$begingroup$

If you are willing to forego GraphicsGrid and give up some control over the placement of the decorations, it can be as simple as this:

Make a 3 x 3 array of graphics (this is adopted from a previous answer}

circles[n_] :=

 Module[{r, cntr}, r := RandomReal[.25];

  cntr := RandomReal[1, {2}];

  Graphics[

   Table[{EdgeForm[Black], Hue[RandomReal[]], Disk[cntr, r]}, n], 

   PlotRange -> {{0, 1}, {0, 1}}, PlotRangeClipping -> True, 

   Frame -> True]



lines[] := 

 Module[{lf, rt}, 

  lf := With[{x = RandomReal[.48]}, {Red, Line[{{x, 0}, {x, 1}}]}];

  rt := With[{x = RandomReal[{.52, 1}]}, {Blue, 

     Line[{{x, 0}, {x, 1}}]}];

  Graphics[{lf, rt}, PlotRange -> {{0, 1}, {0, 1}}, 

   PlotRangeClipping -> True, Frame -> True]]



SeedRandom[4];

graphics =

  Apply[Show, 

   Partition[Transpose[{Table[circles[8], 9], Table[lines[], 9]}], 

    3], {2}];

Make the headers:

{colHeaders, rowHeaders} = Partition[Table[Style[Row[{"Label", i}], "TBI"], {i, 6}], 3];

Make the grid with TableForm:

TableForm[graphics, TableHeadings -> {rowHeaders, colHeaders}]

share

answered 9 mins ago

m_goldbergm_goldberg

87.7k872198

$endgroup$

add a comment | 

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1

$begingroup$

Here is an option:

plots = Table[Table[Plot[Sin[i x + j], {x, 1, 10}], {i, 3}], {j, 3}];

xlabels = {"", "Label 1", "Label 2", "Label 3"};

ylabels = {"Label 4", "Label 5", "Label 6"};

GraphicsGrid[Join[{xlabels}, Transpose[Join[{ylabels}, Transpose[plots]]]]]

share|improve this answer

answered 2 hours ago

MelaGoMelaGo

4863

$endgroup$

add a comment | 

1

$begingroup$

Here is an option:

plots = Table[Table[Plot[Sin[i x + j], {x, 1, 10}], {i, 3}], {j, 3}];

xlabels = {"", "Label 1", "Label 2", "Label 3"};

ylabels = {"Label 4", "Label 5", "Label 6"};

GraphicsGrid[Join[{xlabels}, Transpose[Join[{ylabels}, Transpose[plots]]]]]

share|improve this answer

answered 2 hours ago

MelaGoMelaGo

4863

$endgroup$

add a comment | 

$begingroup$

Here is an option:

plots = Table[Table[Plot[Sin[i x + j], {x, 1, 10}], {i, 3}], {j, 3}];

xlabels = {"", "Label 1", "Label 2", "Label 3"};

ylabels = {"Label 4", "Label 5", "Label 6"};

GraphicsGrid[Join[{xlabels}, Transpose[Join[{ylabels}, Transpose[plots]]]]]

share|improve this answer

answered 2 hours ago

MelaGoMelaGo

4863

$endgroup$

plots = Table[Table[Plot[Sin[i x + j], {x, 1, 10}], {i, 3}], {j, 3}];

xlabels = {"", "Label 1", "Label 2", "Label 3"};

ylabels = {"Label 4", "Label 5", "Label 6"};

GraphicsGrid[Join[{xlabels}, Transpose[Join[{ylabels}, Transpose[plots]]]]]

share|improve this answer

answered 2 hours ago

MelaGoMelaGo

4863

answered 2 hours ago

MelaGoMelaGo

4863

answered 2 hours ago

MelaGoMelaGo

4863

1

$begingroup$

You could construct Graphics for the row and column headings. Something like this. Would have to adjust the vertical / horizontal placement of the label text.

plotGrid = Table[Plot[Sin[x], {x, 0, 2 Pi}], 2, 2];



plotRowHeader = 

 Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 2}];



plotColumnHeader = 

  Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 3, 

     4}] // Prepend[Graphics[Style[Text["X"], 12]]];



graphicsGrid = 

  plotGrid // Prepend[plotRowHeader] // Transpose // 

   Prepend[plotColumnHeader];



GraphicsGrid[graphicsGrid]

share|improve this answer

answered 2 hours ago

Rohit NamjoshiRohit Namjoshi

1,4821213

$endgroup$

add a comment | 

1

$begingroup$

You could construct Graphics for the row and column headings. Something like this. Would have to adjust the vertical / horizontal placement of the label text.

plotGrid = Table[Plot[Sin[x], {x, 0, 2 Pi}], 2, 2];



plotRowHeader = 

 Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 2}];



plotColumnHeader = 

  Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 3, 

     4}] // Prepend[Graphics[Style[Text["X"], 12]]];



graphicsGrid = 

  plotGrid // Prepend[plotRowHeader] // Transpose // 

   Prepend[plotColumnHeader];



GraphicsGrid[graphicsGrid]

share|improve this answer

answered 2 hours ago

Rohit NamjoshiRohit Namjoshi

1,4821213

$endgroup$

add a comment | 

$begingroup$

You could construct Graphics for the row and column headings. Something like this. Would have to adjust the vertical / horizontal placement of the label text.

plotGrid = Table[Plot[Sin[x], {x, 0, 2 Pi}], 2, 2];



plotRowHeader = 

 Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 2}];



plotColumnHeader = 

  Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 3, 

     4}] // Prepend[Graphics[Style[Text["X"], 12]]];



graphicsGrid = 

  plotGrid // Prepend[plotRowHeader] // Transpose // 

   Prepend[plotColumnHeader];



GraphicsGrid[graphicsGrid]

share|improve this answer

answered 2 hours ago

Rohit NamjoshiRohit Namjoshi

1,4821213

$endgroup$

plotGrid = Table[Plot[Sin[x], {x, 0, 2 Pi}], 2, 2];



plotRowHeader = 

 Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 2}];



plotColumnHeader = 

  Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 3, 

     4}] // Prepend[Graphics[Style[Text["X"], 12]]];



graphicsGrid = 

  plotGrid // Prepend[plotRowHeader] // Transpose // 

   Prepend[plotColumnHeader];



GraphicsGrid[graphicsGrid]

share|improve this answer

answered 2 hours ago

Rohit NamjoshiRohit Namjoshi

1,4821213

answered 2 hours ago

Rohit NamjoshiRohit Namjoshi

1,4821213

answered 2 hours ago

Rohit NamjoshiRohit Namjoshi

1,4821213

1

$begingroup$

If you are willing to forego GraphicsGrid and give up some control over the placement of the decorations, it can be as simple as this:

Make a 3 x 3 array of graphics (this is adopted from a previous answer}

circles[n_] :=

 Module[{r, cntr}, r := RandomReal[.25];

  cntr := RandomReal[1, {2}];

  Graphics[

   Table[{EdgeForm[Black], Hue[RandomReal[]], Disk[cntr, r]}, n], 

   PlotRange -> {{0, 1}, {0, 1}}, PlotRangeClipping -> True, 

   Frame -> True]



lines[] := 

 Module[{lf, rt}, 

  lf := With[{x = RandomReal[.48]}, {Red, Line[{{x, 0}, {x, 1}}]}];

  rt := With[{x = RandomReal[{.52, 1}]}, {Blue, 

     Line[{{x, 0}, {x, 1}}]}];

  Graphics[{lf, rt}, PlotRange -> {{0, 1}, {0, 1}}, 

   PlotRangeClipping -> True, Frame -> True]]



SeedRandom[4];

graphics =

  Apply[Show, 

   Partition[Transpose[{Table[circles[8], 9], Table[lines[], 9]}], 

    3], {2}];

Make the headers:

{colHeaders, rowHeaders} = Partition[Table[Style[Row[{"Label", i}], "TBI"], {i, 6}], 3];

Make the grid with TableForm:

TableForm[graphics, TableHeadings -> {rowHeaders, colHeaders}]

share

answered 9 mins ago

m_goldbergm_goldberg

87.7k872198

$endgroup$

add a comment | 

1

$begingroup$

If you are willing to forego GraphicsGrid and give up some control over the placement of the decorations, it can be as simple as this:

Make a 3 x 3 array of graphics (this is adopted from a previous answer}

circles[n_] :=

 Module[{r, cntr}, r := RandomReal[.25];

  cntr := RandomReal[1, {2}];

  Graphics[

   Table[{EdgeForm[Black], Hue[RandomReal[]], Disk[cntr, r]}, n], 

   PlotRange -> {{0, 1}, {0, 1}}, PlotRangeClipping -> True, 

   Frame -> True]



lines[] := 

 Module[{lf, rt}, 

  lf := With[{x = RandomReal[.48]}, {Red, Line[{{x, 0}, {x, 1}}]}];

  rt := With[{x = RandomReal[{.52, 1}]}, {Blue, 

     Line[{{x, 0}, {x, 1}}]}];

  Graphics[{lf, rt}, PlotRange -> {{0, 1}, {0, 1}}, 

   PlotRangeClipping -> True, Frame -> True]]



SeedRandom[4];

graphics =

  Apply[Show, 

   Partition[Transpose[{Table[circles[8], 9], Table[lines[], 9]}], 

    3], {2}];

Make the headers:

{colHeaders, rowHeaders} = Partition[Table[Style[Row[{"Label", i}], "TBI"], {i, 6}], 3];

Make the grid with TableForm:

TableForm[graphics, TableHeadings -> {rowHeaders, colHeaders}]

share

answered 9 mins ago

m_goldbergm_goldberg

87.7k872198

$endgroup$

add a comment | 

$begingroup$

If you are willing to forego GraphicsGrid and give up some control over the placement of the decorations, it can be as simple as this:

Make a 3 x 3 array of graphics (this is adopted from a previous answer}

circles[n_] :=

 Module[{r, cntr}, r := RandomReal[.25];

  cntr := RandomReal[1, {2}];

  Graphics[

   Table[{EdgeForm[Black], Hue[RandomReal[]], Disk[cntr, r]}, n], 

   PlotRange -> {{0, 1}, {0, 1}}, PlotRangeClipping -> True, 

   Frame -> True]



lines[] := 

 Module[{lf, rt}, 

  lf := With[{x = RandomReal[.48]}, {Red, Line[{{x, 0}, {x, 1}}]}];

  rt := With[{x = RandomReal[{.52, 1}]}, {Blue, 

     Line[{{x, 0}, {x, 1}}]}];

  Graphics[{lf, rt}, PlotRange -> {{0, 1}, {0, 1}}, 

   PlotRangeClipping -> True, Frame -> True]]



SeedRandom[4];

graphics =

  Apply[Show, 

   Partition[Transpose[{Table[circles[8], 9], Table[lines[], 9]}], 

    3], {2}];

Make the headers:

{colHeaders, rowHeaders} = Partition[Table[Style[Row[{"Label", i}], "TBI"], {i, 6}], 3];

Make the grid with TableForm:

TableForm[graphics, TableHeadings -> {rowHeaders, colHeaders}]

share

answered 9 mins ago

m_goldbergm_goldberg

87.7k872198

$endgroup$

circles[n_] :=

 Module[{r, cntr}, r := RandomReal[.25];

  cntr := RandomReal[1, {2}];

  Graphics[

   Table[{EdgeForm[Black], Hue[RandomReal[]], Disk[cntr, r]}, n], 

   PlotRange -> {{0, 1}, {0, 1}}, PlotRangeClipping -> True, 

   Frame -> True]



lines[] := 

 Module[{lf, rt}, 

  lf := With[{x = RandomReal[.48]}, {Red, Line[{{x, 0}, {x, 1}}]}];

  rt := With[{x = RandomReal[{.52, 1}]}, {Blue, 

     Line[{{x, 0}, {x, 1}}]}];

  Graphics[{lf, rt}, PlotRange -> {{0, 1}, {0, 1}}, 

   PlotRangeClipping -> True, Frame -> True]]



SeedRandom[4];

graphics =

  Apply[Show, 

   Partition[Transpose[{Table[circles[8], 9], Table[lines[], 9]}], 

    3], {2}];

{colHeaders, rowHeaders} = Partition[Table[Style[Row[{"Label", i}], "TBI"], {i, 6}], 3];

TableForm[graphics, TableHeadings -> {rowHeaders, colHeaders}]

share

answered 9 mins ago

m_goldbergm_goldberg

87.7k872198

answered 9 mins ago

m_goldbergm_goldberg

87.7k872198

answered 9 mins ago

m_goldbergm_goldberg

87.7k872198