What would happen to a modern skyscraper if it rains micro blackholes?What would happen if the black hole at...
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What would happen to a modern skyscraper if it rains micro blackholes?
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What would happen to a modern skyscraper if it rains micro blackholes?
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$begingroup$
Set in present day New York City, an unknown spacecraft of alien origin expelled millions of micro blackholes each with the mass of a grape in the earth atmosphere. I like to know what happens if these millions of micro blackholes were to fall on building structures such as skyscrapers, would it trigger an extinction level event?
apocalypse weapon-mass-destruction black-holes extinction
$endgroup$
add a comment |
$begingroup$
Set in present day New York City, an unknown spacecraft of alien origin expelled millions of micro blackholes each with the mass of a grape in the earth atmosphere. I like to know what happens if these millions of micro blackholes were to fall on building structures such as skyscrapers, would it trigger an extinction level event?
apocalypse weapon-mass-destruction black-holes extinction
$endgroup$
1
$begingroup$
Given the aliens could easily send waves of asteroids to destroy Earth's surface completely with practically trivial effort (at their tech level), mucking around with micro black holes (or any black holes) seems quite daft.
$endgroup$
– StephenG
5 hours ago
$begingroup$
How about they expell at fraction of c so we take length contraction into question?
$endgroup$
– user6760
5 hours ago
add a comment |
$begingroup$
Set in present day New York City, an unknown spacecraft of alien origin expelled millions of micro blackholes each with the mass of a grape in the earth atmosphere. I like to know what happens if these millions of micro blackholes were to fall on building structures such as skyscrapers, would it trigger an extinction level event?
apocalypse weapon-mass-destruction black-holes extinction
$endgroup$
Set in present day New York City, an unknown spacecraft of alien origin expelled millions of micro blackholes each with the mass of a grape in the earth atmosphere. I like to know what happens if these millions of micro blackholes were to fall on building structures such as skyscrapers, would it trigger an extinction level event?
apocalypse weapon-mass-destruction black-holes extinction
apocalypse weapon-mass-destruction black-holes extinction
edited 4 hours ago
Renan
52.6k15120261
52.6k15120261
asked 5 hours ago
user6760user6760
13.5k1676165
13.5k1676165
1
$begingroup$
Given the aliens could easily send waves of asteroids to destroy Earth's surface completely with practically trivial effort (at their tech level), mucking around with micro black holes (or any black holes) seems quite daft.
$endgroup$
– StephenG
5 hours ago
$begingroup$
How about they expell at fraction of c so we take length contraction into question?
$endgroup$
– user6760
5 hours ago
add a comment |
1
$begingroup$
Given the aliens could easily send waves of asteroids to destroy Earth's surface completely with practically trivial effort (at their tech level), mucking around with micro black holes (or any black holes) seems quite daft.
$endgroup$
– StephenG
5 hours ago
$begingroup$
How about they expell at fraction of c so we take length contraction into question?
$endgroup$
– user6760
5 hours ago
1
1
$begingroup$
Given the aliens could easily send waves of asteroids to destroy Earth's surface completely with practically trivial effort (at their tech level), mucking around with micro black holes (or any black holes) seems quite daft.
$endgroup$
– StephenG
5 hours ago
$begingroup$
Given the aliens could easily send waves of asteroids to destroy Earth's surface completely with practically trivial effort (at their tech level), mucking around with micro black holes (or any black holes) seems quite daft.
$endgroup$
– StephenG
5 hours ago
$begingroup$
How about they expell at fraction of c so we take length contraction into question?
$endgroup$
– user6760
5 hours ago
$begingroup$
How about they expell at fraction of c so we take length contraction into question?
$endgroup$
– user6760
5 hours ago
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
would it triggers extinction level event?
Since they'd evaporate more or less instantaneously (known as Hawking radiation), releasing energy according to the famous equation beginning E=, the spaceship would last a few microseconds at best, Earth would be fine.
Yes, the aliens in the ship would become extinct.
$endgroup$
3
$begingroup$
According to this calculator (eguruchela.com/physics/calculator/…), they would last 1.6581375e-29 seconds. There is also the fact that their radius would be so small, that they wouldn't even interact with atoms most of the time.
$endgroup$
– Tyler S. Loeper
5 hours ago
$begingroup$
@TylerS.Loeper Gosh, we don't have an SI multiplier to express that, atto is feeling left out and lonely.
$endgroup$
– Agrajag
5 hours ago
$begingroup$
How about they just pick the right size black holes that they evaporate with a boom after they reach Earth? That shouldn't be too hard. They'd only be grape sized for a tiny while, but that's fine.
$endgroup$
– John Dvorak
4 hours ago
add a comment |
$begingroup$
Black holes evaporate by emitting Hawking radiation
a 1-second-life black hole has a mass of $2.28 cdot 10^5 kg$
A grape has far less mass than that, thus the black hole would evaporate way faster than that.
An intelligent life form dropping micro black holes on Earth would thus quickly annihilate its own bombing squad in a shower of gamma ray, proving that they were not so intelligent as we thought.
$endgroup$
add a comment |
$begingroup$
The electromagnetic force from one electron on another and the gravitational force of this micro-black hole both follow an inverse square law. A grape about 1.5 cm in radius would have a mass of about 0.015 kg.
When does the gravitational force of the grape exceed the electromagnetic force between electrons ? It's when :
$$frac r R < sqrt{frac {4pi epsilon_0Gm_em_h}{e^2}} = 6.3times 10^{-8}$$
Meaning the black hole would have to pass less than one ten millionth of the distance between electrons to have a significant influence on one. Away from than range the electron will happily go about it's business hardly disturbed at all.
Even if a black hole passes this close the effect is only temporary. You're still nowhere near the event horizon of that black hole and so the electron will, at worst, be pulled away from it's normal motion and after some brief period when the black hole moves away it will simply recombined in some way with the bulk of atoms around it. It might cause a minute amount of damage on a molecular level (even allowing for millions of these micro black holes), but the net effect would be tiny, probably less that someone hitting a wall with their hand.
How about they expell at fraction of c so we take length contraction into question?
You seem to mean that to avoid Hawking radiation evaporation destroying these black holes before they even reach the black hole, they could be ejected at a high fraction of the speed of light.
So how high a speed is needed to avoid them evaporating before they travel 100 meters, assuming your aliens like low level flying ?
The fraction of the speed of light needed is :
$$frac v c > frac 1 { sqrt{ 1 + left( frac {Tc} L right)^2 } }$$
Where $L$ is the distance they must travel and $T$ is the lifetime of the micro black hole before it evaporates.
This works out at $frac v c approx 1 - 2times 10^{-19}$. That's insanely close to the speed of light.
A million grapes of mass 0.015 kg will have a mass of 15,000 kg. But the energy required to get them moving at this insane fraction of the speed of light would be enormous. It equates to a mass about $2times 10^9$ times 15,000 kg. Or to put it another way, the ship firing these micro black holes would need to have a mass-energy of about $3times 10^{13}$ kg. The asteroid Vesta is substantially larger than this.
So this is actually a small mass in terms of asteroids and you could probably destroy Earth a lot more easily simply by grabbing some handy largish asteroids and sending them on their merry way towards Earth at some modest speed that's easily imparted with your spaceship.
Conclusion :
No need at all to mess around with ultra-relativistic micro-black holes when the universe provides you with much simpler and easy to handle "ammunition" in the form of basic asteroids.
$endgroup$
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
would it triggers extinction level event?
Since they'd evaporate more or less instantaneously (known as Hawking radiation), releasing energy according to the famous equation beginning E=, the spaceship would last a few microseconds at best, Earth would be fine.
Yes, the aliens in the ship would become extinct.
$endgroup$
3
$begingroup$
According to this calculator (eguruchela.com/physics/calculator/…), they would last 1.6581375e-29 seconds. There is also the fact that their radius would be so small, that they wouldn't even interact with atoms most of the time.
$endgroup$
– Tyler S. Loeper
5 hours ago
$begingroup$
@TylerS.Loeper Gosh, we don't have an SI multiplier to express that, atto is feeling left out and lonely.
$endgroup$
– Agrajag
5 hours ago
$begingroup$
How about they just pick the right size black holes that they evaporate with a boom after they reach Earth? That shouldn't be too hard. They'd only be grape sized for a tiny while, but that's fine.
$endgroup$
– John Dvorak
4 hours ago
add a comment |
$begingroup$
would it triggers extinction level event?
Since they'd evaporate more or less instantaneously (known as Hawking radiation), releasing energy according to the famous equation beginning E=, the spaceship would last a few microseconds at best, Earth would be fine.
Yes, the aliens in the ship would become extinct.
$endgroup$
3
$begingroup$
According to this calculator (eguruchela.com/physics/calculator/…), they would last 1.6581375e-29 seconds. There is also the fact that their radius would be so small, that they wouldn't even interact with atoms most of the time.
$endgroup$
– Tyler S. Loeper
5 hours ago
$begingroup$
@TylerS.Loeper Gosh, we don't have an SI multiplier to express that, atto is feeling left out and lonely.
$endgroup$
– Agrajag
5 hours ago
$begingroup$
How about they just pick the right size black holes that they evaporate with a boom after they reach Earth? That shouldn't be too hard. They'd only be grape sized for a tiny while, but that's fine.
$endgroup$
– John Dvorak
4 hours ago
add a comment |
$begingroup$
would it triggers extinction level event?
Since they'd evaporate more or less instantaneously (known as Hawking radiation), releasing energy according to the famous equation beginning E=, the spaceship would last a few microseconds at best, Earth would be fine.
Yes, the aliens in the ship would become extinct.
$endgroup$
would it triggers extinction level event?
Since they'd evaporate more or less instantaneously (known as Hawking radiation), releasing energy according to the famous equation beginning E=, the spaceship would last a few microseconds at best, Earth would be fine.
Yes, the aliens in the ship would become extinct.
answered 5 hours ago
AgrajagAgrajag
6,84911349
6,84911349
3
$begingroup$
According to this calculator (eguruchela.com/physics/calculator/…), they would last 1.6581375e-29 seconds. There is also the fact that their radius would be so small, that they wouldn't even interact with atoms most of the time.
$endgroup$
– Tyler S. Loeper
5 hours ago
$begingroup$
@TylerS.Loeper Gosh, we don't have an SI multiplier to express that, atto is feeling left out and lonely.
$endgroup$
– Agrajag
5 hours ago
$begingroup$
How about they just pick the right size black holes that they evaporate with a boom after they reach Earth? That shouldn't be too hard. They'd only be grape sized for a tiny while, but that's fine.
$endgroup$
– John Dvorak
4 hours ago
add a comment |
3
$begingroup$
According to this calculator (eguruchela.com/physics/calculator/…), they would last 1.6581375e-29 seconds. There is also the fact that their radius would be so small, that they wouldn't even interact with atoms most of the time.
$endgroup$
– Tyler S. Loeper
5 hours ago
$begingroup$
@TylerS.Loeper Gosh, we don't have an SI multiplier to express that, atto is feeling left out and lonely.
$endgroup$
– Agrajag
5 hours ago
$begingroup$
How about they just pick the right size black holes that they evaporate with a boom after they reach Earth? That shouldn't be too hard. They'd only be grape sized for a tiny while, but that's fine.
$endgroup$
– John Dvorak
4 hours ago
3
3
$begingroup$
According to this calculator (eguruchela.com/physics/calculator/…), they would last 1.6581375e-29 seconds. There is also the fact that their radius would be so small, that they wouldn't even interact with atoms most of the time.
$endgroup$
– Tyler S. Loeper
5 hours ago
$begingroup$
According to this calculator (eguruchela.com/physics/calculator/…), they would last 1.6581375e-29 seconds. There is also the fact that their radius would be so small, that they wouldn't even interact with atoms most of the time.
$endgroup$
– Tyler S. Loeper
5 hours ago
$begingroup$
@TylerS.Loeper Gosh, we don't have an SI multiplier to express that, atto is feeling left out and lonely.
$endgroup$
– Agrajag
5 hours ago
$begingroup$
@TylerS.Loeper Gosh, we don't have an SI multiplier to express that, atto is feeling left out and lonely.
$endgroup$
– Agrajag
5 hours ago
$begingroup$
How about they just pick the right size black holes that they evaporate with a boom after they reach Earth? That shouldn't be too hard. They'd only be grape sized for a tiny while, but that's fine.
$endgroup$
– John Dvorak
4 hours ago
$begingroup$
How about they just pick the right size black holes that they evaporate with a boom after they reach Earth? That shouldn't be too hard. They'd only be grape sized for a tiny while, but that's fine.
$endgroup$
– John Dvorak
4 hours ago
add a comment |
$begingroup$
Black holes evaporate by emitting Hawking radiation
a 1-second-life black hole has a mass of $2.28 cdot 10^5 kg$
A grape has far less mass than that, thus the black hole would evaporate way faster than that.
An intelligent life form dropping micro black holes on Earth would thus quickly annihilate its own bombing squad in a shower of gamma ray, proving that they were not so intelligent as we thought.
$endgroup$
add a comment |
$begingroup$
Black holes evaporate by emitting Hawking radiation
a 1-second-life black hole has a mass of $2.28 cdot 10^5 kg$
A grape has far less mass than that, thus the black hole would evaporate way faster than that.
An intelligent life form dropping micro black holes on Earth would thus quickly annihilate its own bombing squad in a shower of gamma ray, proving that they were not so intelligent as we thought.
$endgroup$
add a comment |
$begingroup$
Black holes evaporate by emitting Hawking radiation
a 1-second-life black hole has a mass of $2.28 cdot 10^5 kg$
A grape has far less mass than that, thus the black hole would evaporate way faster than that.
An intelligent life form dropping micro black holes on Earth would thus quickly annihilate its own bombing squad in a shower of gamma ray, proving that they were not so intelligent as we thought.
$endgroup$
Black holes evaporate by emitting Hawking radiation
a 1-second-life black hole has a mass of $2.28 cdot 10^5 kg$
A grape has far less mass than that, thus the black hole would evaporate way faster than that.
An intelligent life form dropping micro black holes on Earth would thus quickly annihilate its own bombing squad in a shower of gamma ray, proving that they were not so intelligent as we thought.
answered 5 hours ago
L.Dutch♦L.Dutch
90.3k29209436
90.3k29209436
add a comment |
add a comment |
$begingroup$
The electromagnetic force from one electron on another and the gravitational force of this micro-black hole both follow an inverse square law. A grape about 1.5 cm in radius would have a mass of about 0.015 kg.
When does the gravitational force of the grape exceed the electromagnetic force between electrons ? It's when :
$$frac r R < sqrt{frac {4pi epsilon_0Gm_em_h}{e^2}} = 6.3times 10^{-8}$$
Meaning the black hole would have to pass less than one ten millionth of the distance between electrons to have a significant influence on one. Away from than range the electron will happily go about it's business hardly disturbed at all.
Even if a black hole passes this close the effect is only temporary. You're still nowhere near the event horizon of that black hole and so the electron will, at worst, be pulled away from it's normal motion and after some brief period when the black hole moves away it will simply recombined in some way with the bulk of atoms around it. It might cause a minute amount of damage on a molecular level (even allowing for millions of these micro black holes), but the net effect would be tiny, probably less that someone hitting a wall with their hand.
How about they expell at fraction of c so we take length contraction into question?
You seem to mean that to avoid Hawking radiation evaporation destroying these black holes before they even reach the black hole, they could be ejected at a high fraction of the speed of light.
So how high a speed is needed to avoid them evaporating before they travel 100 meters, assuming your aliens like low level flying ?
The fraction of the speed of light needed is :
$$frac v c > frac 1 { sqrt{ 1 + left( frac {Tc} L right)^2 } }$$
Where $L$ is the distance they must travel and $T$ is the lifetime of the micro black hole before it evaporates.
This works out at $frac v c approx 1 - 2times 10^{-19}$. That's insanely close to the speed of light.
A million grapes of mass 0.015 kg will have a mass of 15,000 kg. But the energy required to get them moving at this insane fraction of the speed of light would be enormous. It equates to a mass about $2times 10^9$ times 15,000 kg. Or to put it another way, the ship firing these micro black holes would need to have a mass-energy of about $3times 10^{13}$ kg. The asteroid Vesta is substantially larger than this.
So this is actually a small mass in terms of asteroids and you could probably destroy Earth a lot more easily simply by grabbing some handy largish asteroids and sending them on their merry way towards Earth at some modest speed that's easily imparted with your spaceship.
Conclusion :
No need at all to mess around with ultra-relativistic micro-black holes when the universe provides you with much simpler and easy to handle "ammunition" in the form of basic asteroids.
$endgroup$
add a comment |
$begingroup$
The electromagnetic force from one electron on another and the gravitational force of this micro-black hole both follow an inverse square law. A grape about 1.5 cm in radius would have a mass of about 0.015 kg.
When does the gravitational force of the grape exceed the electromagnetic force between electrons ? It's when :
$$frac r R < sqrt{frac {4pi epsilon_0Gm_em_h}{e^2}} = 6.3times 10^{-8}$$
Meaning the black hole would have to pass less than one ten millionth of the distance between electrons to have a significant influence on one. Away from than range the electron will happily go about it's business hardly disturbed at all.
Even if a black hole passes this close the effect is only temporary. You're still nowhere near the event horizon of that black hole and so the electron will, at worst, be pulled away from it's normal motion and after some brief period when the black hole moves away it will simply recombined in some way with the bulk of atoms around it. It might cause a minute amount of damage on a molecular level (even allowing for millions of these micro black holes), but the net effect would be tiny, probably less that someone hitting a wall with their hand.
How about they expell at fraction of c so we take length contraction into question?
You seem to mean that to avoid Hawking radiation evaporation destroying these black holes before they even reach the black hole, they could be ejected at a high fraction of the speed of light.
So how high a speed is needed to avoid them evaporating before they travel 100 meters, assuming your aliens like low level flying ?
The fraction of the speed of light needed is :
$$frac v c > frac 1 { sqrt{ 1 + left( frac {Tc} L right)^2 } }$$
Where $L$ is the distance they must travel and $T$ is the lifetime of the micro black hole before it evaporates.
This works out at $frac v c approx 1 - 2times 10^{-19}$. That's insanely close to the speed of light.
A million grapes of mass 0.015 kg will have a mass of 15,000 kg. But the energy required to get them moving at this insane fraction of the speed of light would be enormous. It equates to a mass about $2times 10^9$ times 15,000 kg. Or to put it another way, the ship firing these micro black holes would need to have a mass-energy of about $3times 10^{13}$ kg. The asteroid Vesta is substantially larger than this.
So this is actually a small mass in terms of asteroids and you could probably destroy Earth a lot more easily simply by grabbing some handy largish asteroids and sending them on their merry way towards Earth at some modest speed that's easily imparted with your spaceship.
Conclusion :
No need at all to mess around with ultra-relativistic micro-black holes when the universe provides you with much simpler and easy to handle "ammunition" in the form of basic asteroids.
$endgroup$
add a comment |
$begingroup$
The electromagnetic force from one electron on another and the gravitational force of this micro-black hole both follow an inverse square law. A grape about 1.5 cm in radius would have a mass of about 0.015 kg.
When does the gravitational force of the grape exceed the electromagnetic force between electrons ? It's when :
$$frac r R < sqrt{frac {4pi epsilon_0Gm_em_h}{e^2}} = 6.3times 10^{-8}$$
Meaning the black hole would have to pass less than one ten millionth of the distance between electrons to have a significant influence on one. Away from than range the electron will happily go about it's business hardly disturbed at all.
Even if a black hole passes this close the effect is only temporary. You're still nowhere near the event horizon of that black hole and so the electron will, at worst, be pulled away from it's normal motion and after some brief period when the black hole moves away it will simply recombined in some way with the bulk of atoms around it. It might cause a minute amount of damage on a molecular level (even allowing for millions of these micro black holes), but the net effect would be tiny, probably less that someone hitting a wall with their hand.
How about they expell at fraction of c so we take length contraction into question?
You seem to mean that to avoid Hawking radiation evaporation destroying these black holes before they even reach the black hole, they could be ejected at a high fraction of the speed of light.
So how high a speed is needed to avoid them evaporating before they travel 100 meters, assuming your aliens like low level flying ?
The fraction of the speed of light needed is :
$$frac v c > frac 1 { sqrt{ 1 + left( frac {Tc} L right)^2 } }$$
Where $L$ is the distance they must travel and $T$ is the lifetime of the micro black hole before it evaporates.
This works out at $frac v c approx 1 - 2times 10^{-19}$. That's insanely close to the speed of light.
A million grapes of mass 0.015 kg will have a mass of 15,000 kg. But the energy required to get them moving at this insane fraction of the speed of light would be enormous. It equates to a mass about $2times 10^9$ times 15,000 kg. Or to put it another way, the ship firing these micro black holes would need to have a mass-energy of about $3times 10^{13}$ kg. The asteroid Vesta is substantially larger than this.
So this is actually a small mass in terms of asteroids and you could probably destroy Earth a lot more easily simply by grabbing some handy largish asteroids and sending them on their merry way towards Earth at some modest speed that's easily imparted with your spaceship.
Conclusion :
No need at all to mess around with ultra-relativistic micro-black holes when the universe provides you with much simpler and easy to handle "ammunition" in the form of basic asteroids.
$endgroup$
The electromagnetic force from one electron on another and the gravitational force of this micro-black hole both follow an inverse square law. A grape about 1.5 cm in radius would have a mass of about 0.015 kg.
When does the gravitational force of the grape exceed the electromagnetic force between electrons ? It's when :
$$frac r R < sqrt{frac {4pi epsilon_0Gm_em_h}{e^2}} = 6.3times 10^{-8}$$
Meaning the black hole would have to pass less than one ten millionth of the distance between electrons to have a significant influence on one. Away from than range the electron will happily go about it's business hardly disturbed at all.
Even if a black hole passes this close the effect is only temporary. You're still nowhere near the event horizon of that black hole and so the electron will, at worst, be pulled away from it's normal motion and after some brief period when the black hole moves away it will simply recombined in some way with the bulk of atoms around it. It might cause a minute amount of damage on a molecular level (even allowing for millions of these micro black holes), but the net effect would be tiny, probably less that someone hitting a wall with their hand.
How about they expell at fraction of c so we take length contraction into question?
You seem to mean that to avoid Hawking radiation evaporation destroying these black holes before they even reach the black hole, they could be ejected at a high fraction of the speed of light.
So how high a speed is needed to avoid them evaporating before they travel 100 meters, assuming your aliens like low level flying ?
The fraction of the speed of light needed is :
$$frac v c > frac 1 { sqrt{ 1 + left( frac {Tc} L right)^2 } }$$
Where $L$ is the distance they must travel and $T$ is the lifetime of the micro black hole before it evaporates.
This works out at $frac v c approx 1 - 2times 10^{-19}$. That's insanely close to the speed of light.
A million grapes of mass 0.015 kg will have a mass of 15,000 kg. But the energy required to get them moving at this insane fraction of the speed of light would be enormous. It equates to a mass about $2times 10^9$ times 15,000 kg. Or to put it another way, the ship firing these micro black holes would need to have a mass-energy of about $3times 10^{13}$ kg. The asteroid Vesta is substantially larger than this.
So this is actually a small mass in terms of asteroids and you could probably destroy Earth a lot more easily simply by grabbing some handy largish asteroids and sending them on their merry way towards Earth at some modest speed that's easily imparted with your spaceship.
Conclusion :
No need at all to mess around with ultra-relativistic micro-black holes when the universe provides you with much simpler and easy to handle "ammunition" in the form of basic asteroids.
answered 4 hours ago
StephenGStephenG
14.1k72051
14.1k72051
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1
$begingroup$
Given the aliens could easily send waves of asteroids to destroy Earth's surface completely with practically trivial effort (at their tech level), mucking around with micro black holes (or any black holes) seems quite daft.
$endgroup$
– StephenG
5 hours ago
$begingroup$
How about they expell at fraction of c so we take length contraction into question?
$endgroup$
– user6760
5 hours ago