What is the accessibility of a package's `Private` context variables? The 2019 Stack Overflow...
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What is the accessibility of a package's `Private` context variables?
The 2019 Stack Overflow Developer Survey Results Are InHow symbol lookup actually worksWhat are recommended guidelines for developing packages?How to properly handle mutual imports of multiple packages?How can Private functions be made completely opaque?Does one need to be careful about loading multiple (many) contexts or packages in the same session?WebServices context problemHow to pass rules to packagesA question regarding shadowed symbolsIs there any harm or benefit to Removing unneeded private symbols in packages?Information (??) of function defined in Package return the function with long name of variablesHow to resolve a context shadow problem (revised)
$begingroup$
I've been reading up on how Mathematica handles contexts, $Context, $ContextPath, and a few of the tutorials they have on Packages.
What I'm wondering about is how the functions defined in, say, CustomPackage` are able to access the variables in CustomPackage`Private`.
For example,
BeginPackage["CustomPackage`"]
MyFunction::usage = "MyFunction[arg1] adds 5 to arg1."
Begin["`Private`"]
abc=5;
MyFunction[arg1_] := arg1 + abc;
End[]
EndPackage[]
When I load the package <<CustomPackage` the $ContextPath will have CustomPackage` on it, but not CustomPackage`Private`
So how does MyFunction know the value of abc at the delayed function call (when it is called) if the Private` context isn't on the $ContextPath
packages core-language scoping contexts
$endgroup$
add a comment |
$begingroup$
I've been reading up on how Mathematica handles contexts, $Context, $ContextPath, and a few of the tutorials they have on Packages.
What I'm wondering about is how the functions defined in, say, CustomPackage` are able to access the variables in CustomPackage`Private`.
For example,
BeginPackage["CustomPackage`"]
MyFunction::usage = "MyFunction[arg1] adds 5 to arg1."
Begin["`Private`"]
abc=5;
MyFunction[arg1_] := arg1 + abc;
End[]
EndPackage[]
When I load the package <<CustomPackage` the $ContextPath will have CustomPackage` on it, but not CustomPackage`Private`
So how does MyFunction know the value of abc at the delayed function call (when it is called) if the Private` context isn't on the $ContextPath
packages core-language scoping contexts
$endgroup$
add a comment |
$begingroup$
I've been reading up on how Mathematica handles contexts, $Context, $ContextPath, and a few of the tutorials they have on Packages.
What I'm wondering about is how the functions defined in, say, CustomPackage` are able to access the variables in CustomPackage`Private`.
For example,
BeginPackage["CustomPackage`"]
MyFunction::usage = "MyFunction[arg1] adds 5 to arg1."
Begin["`Private`"]
abc=5;
MyFunction[arg1_] := arg1 + abc;
End[]
EndPackage[]
When I load the package <<CustomPackage` the $ContextPath will have CustomPackage` on it, but not CustomPackage`Private`
So how does MyFunction know the value of abc at the delayed function call (when it is called) if the Private` context isn't on the $ContextPath
packages core-language scoping contexts
$endgroup$
I've been reading up on how Mathematica handles contexts, $Context, $ContextPath, and a few of the tutorials they have on Packages.
What I'm wondering about is how the functions defined in, say, CustomPackage` are able to access the variables in CustomPackage`Private`.
For example,
BeginPackage["CustomPackage`"]
MyFunction::usage = "MyFunction[arg1] adds 5 to arg1."
Begin["`Private`"]
abc=5;
MyFunction[arg1_] := arg1 + abc;
End[]
EndPackage[]
When I load the package <<CustomPackage` the $ContextPath will have CustomPackage` on it, but not CustomPackage`Private`
So how does MyFunction know the value of abc at the delayed function call (when it is called) if the Private` context isn't on the $ContextPath
packages core-language scoping contexts
packages core-language scoping contexts
edited 13 mins ago
m_goldberg
88.5k873200
88.5k873200
asked 3 hours ago
w1resw1res
1934
1934
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
All symbols are created at load time, so when you do:
BeginPackage["X`"];
x::usage="Declaring x as an exported symbol in the X` context";
Begin["`SomePrivateContext`"];
x[a_]:=b
End[];
EndPackage[];
x was created as X`x but the DownValues of x reference X`SomePrivateContext`a and X`SomePrivateContext`b which were created at the time the function was defined. These symbols are unique, so that reference only ever points that a single object.
$endgroup$
add a comment |
$begingroup$
Begin["`Private`"]; sets the current $Context to "CustomPackage `Private`". This causes two things:
The symbol
abcwill be searched in the current context first, thus in"CustomPackage`Private`". Only if it is not found there, the search goes on along$ContextPath.If no matching symbol is found this way, a new symbol
abcis created, namely in the current$Contextwhich is"CustomPackage`Private`". So the full symbol name is"CustomPackage`Private`abc".
For example, running your code in a fresh kernel and executing
??MyFunction
reveals that the full definition of MyFunction is
MyFunction[CustomPackage`Private`arg1_]:=CustomPackage`Private`arg1+CustomPackage`Private`abc
Moreover, with
?*`abc
you see that the only symbol in all contexts that matches abc is CustomPackage`Private`abc and has the value 5 assigned to it.
$endgroup$
add a comment |
$begingroup$
So how does
MyFunctionknow the value ofabcat the delayed function call (when it is called) if thePrivate`context isn't on the$ContextPath
There is a misunderstanding here. You are assuming that abc is searched for in some context only when MyFunction[something] is evaluated. This is not the case.
$Context and $ContextPath only affect how source code is parsed (not how expressions are evaluated). In other words, they only affect how the text you write in the package file is interpreted and converted into in-memory expressions. Once the package has been loaded with Get, this interpretation has already happened. MyFunction has been interpreted as the symbol CustomPackage`MyFunction and abc has been interpreted as CustomPackage`Private`abc, according to the value of $Context and $ContextPath at the time each was read. These are the full names of these symbols and this is how they exist in memory.
Load the package and try this:
Block[{$ContextPath},
Print@Definition[MyFunction]
]
You'll see the following printed:
CustomPackage`MyFunction[CustomPackage`Private`arg1_] :=
CustomPackage`Private`arg1+CustomPackage`Private`abc
As you can see, a context is always associated with every symbol.
$endgroup$
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
All symbols are created at load time, so when you do:
BeginPackage["X`"];
x::usage="Declaring x as an exported symbol in the X` context";
Begin["`SomePrivateContext`"];
x[a_]:=b
End[];
EndPackage[];
x was created as X`x but the DownValues of x reference X`SomePrivateContext`a and X`SomePrivateContext`b which were created at the time the function was defined. These symbols are unique, so that reference only ever points that a single object.
$endgroup$
add a comment |
$begingroup$
All symbols are created at load time, so when you do:
BeginPackage["X`"];
x::usage="Declaring x as an exported symbol in the X` context";
Begin["`SomePrivateContext`"];
x[a_]:=b
End[];
EndPackage[];
x was created as X`x but the DownValues of x reference X`SomePrivateContext`a and X`SomePrivateContext`b which were created at the time the function was defined. These symbols are unique, so that reference only ever points that a single object.
$endgroup$
add a comment |
$begingroup$
All symbols are created at load time, so when you do:
BeginPackage["X`"];
x::usage="Declaring x as an exported symbol in the X` context";
Begin["`SomePrivateContext`"];
x[a_]:=b
End[];
EndPackage[];
x was created as X`x but the DownValues of x reference X`SomePrivateContext`a and X`SomePrivateContext`b which were created at the time the function was defined. These symbols are unique, so that reference only ever points that a single object.
$endgroup$
All symbols are created at load time, so when you do:
BeginPackage["X`"];
x::usage="Declaring x as an exported symbol in the X` context";
Begin["`SomePrivateContext`"];
x[a_]:=b
End[];
EndPackage[];
x was created as X`x but the DownValues of x reference X`SomePrivateContext`a and X`SomePrivateContext`b which were created at the time the function was defined. These symbols are unique, so that reference only ever points that a single object.
answered 3 hours ago
b3m2a1b3m2a1
28.6k359165
28.6k359165
add a comment |
add a comment |
$begingroup$
Begin["`Private`"]; sets the current $Context to "CustomPackage `Private`". This causes two things:
The symbol
abcwill be searched in the current context first, thus in"CustomPackage`Private`". Only if it is not found there, the search goes on along$ContextPath.If no matching symbol is found this way, a new symbol
abcis created, namely in the current$Contextwhich is"CustomPackage`Private`". So the full symbol name is"CustomPackage`Private`abc".
For example, running your code in a fresh kernel and executing
??MyFunction
reveals that the full definition of MyFunction is
MyFunction[CustomPackage`Private`arg1_]:=CustomPackage`Private`arg1+CustomPackage`Private`abc
Moreover, with
?*`abc
you see that the only symbol in all contexts that matches abc is CustomPackage`Private`abc and has the value 5 assigned to it.
$endgroup$
add a comment |
$begingroup$
Begin["`Private`"]; sets the current $Context to "CustomPackage `Private`". This causes two things:
The symbol
abcwill be searched in the current context first, thus in"CustomPackage`Private`". Only if it is not found there, the search goes on along$ContextPath.If no matching symbol is found this way, a new symbol
abcis created, namely in the current$Contextwhich is"CustomPackage`Private`". So the full symbol name is"CustomPackage`Private`abc".
For example, running your code in a fresh kernel and executing
??MyFunction
reveals that the full definition of MyFunction is
MyFunction[CustomPackage`Private`arg1_]:=CustomPackage`Private`arg1+CustomPackage`Private`abc
Moreover, with
?*`abc
you see that the only symbol in all contexts that matches abc is CustomPackage`Private`abc and has the value 5 assigned to it.
$endgroup$
add a comment |
$begingroup$
Begin["`Private`"]; sets the current $Context to "CustomPackage `Private`". This causes two things:
The symbol
abcwill be searched in the current context first, thus in"CustomPackage`Private`". Only if it is not found there, the search goes on along$ContextPath.If no matching symbol is found this way, a new symbol
abcis created, namely in the current$Contextwhich is"CustomPackage`Private`". So the full symbol name is"CustomPackage`Private`abc".
For example, running your code in a fresh kernel and executing
??MyFunction
reveals that the full definition of MyFunction is
MyFunction[CustomPackage`Private`arg1_]:=CustomPackage`Private`arg1+CustomPackage`Private`abc
Moreover, with
?*`abc
you see that the only symbol in all contexts that matches abc is CustomPackage`Private`abc and has the value 5 assigned to it.
$endgroup$
Begin["`Private`"]; sets the current $Context to "CustomPackage `Private`". This causes two things:
The symbol
abcwill be searched in the current context first, thus in"CustomPackage`Private`". Only if it is not found there, the search goes on along$ContextPath.If no matching symbol is found this way, a new symbol
abcis created, namely in the current$Contextwhich is"CustomPackage`Private`". So the full symbol name is"CustomPackage`Private`abc".
For example, running your code in a fresh kernel and executing
??MyFunction
reveals that the full definition of MyFunction is
MyFunction[CustomPackage`Private`arg1_]:=CustomPackage`Private`arg1+CustomPackage`Private`abc
Moreover, with
?*`abc
you see that the only symbol in all contexts that matches abc is CustomPackage`Private`abc and has the value 5 assigned to it.
edited 2 hours ago
answered 2 hours ago
Henrik SchumacherHenrik Schumacher
59.7k582166
59.7k582166
add a comment |
add a comment |
$begingroup$
So how does
MyFunctionknow the value ofabcat the delayed function call (when it is called) if thePrivate`context isn't on the$ContextPath
There is a misunderstanding here. You are assuming that abc is searched for in some context only when MyFunction[something] is evaluated. This is not the case.
$Context and $ContextPath only affect how source code is parsed (not how expressions are evaluated). In other words, they only affect how the text you write in the package file is interpreted and converted into in-memory expressions. Once the package has been loaded with Get, this interpretation has already happened. MyFunction has been interpreted as the symbol CustomPackage`MyFunction and abc has been interpreted as CustomPackage`Private`abc, according to the value of $Context and $ContextPath at the time each was read. These are the full names of these symbols and this is how they exist in memory.
Load the package and try this:
Block[{$ContextPath},
Print@Definition[MyFunction]
]
You'll see the following printed:
CustomPackage`MyFunction[CustomPackage`Private`arg1_] :=
CustomPackage`Private`arg1+CustomPackage`Private`abc
As you can see, a context is always associated with every symbol.
$endgroup$
add a comment |
$begingroup$
So how does
MyFunctionknow the value ofabcat the delayed function call (when it is called) if thePrivate`context isn't on the$ContextPath
There is a misunderstanding here. You are assuming that abc is searched for in some context only when MyFunction[something] is evaluated. This is not the case.
$Context and $ContextPath only affect how source code is parsed (not how expressions are evaluated). In other words, they only affect how the text you write in the package file is interpreted and converted into in-memory expressions. Once the package has been loaded with Get, this interpretation has already happened. MyFunction has been interpreted as the symbol CustomPackage`MyFunction and abc has been interpreted as CustomPackage`Private`abc, according to the value of $Context and $ContextPath at the time each was read. These are the full names of these symbols and this is how they exist in memory.
Load the package and try this:
Block[{$ContextPath},
Print@Definition[MyFunction]
]
You'll see the following printed:
CustomPackage`MyFunction[CustomPackage`Private`arg1_] :=
CustomPackage`Private`arg1+CustomPackage`Private`abc
As you can see, a context is always associated with every symbol.
$endgroup$
add a comment |
$begingroup$
So how does
MyFunctionknow the value ofabcat the delayed function call (when it is called) if thePrivate`context isn't on the$ContextPath
There is a misunderstanding here. You are assuming that abc is searched for in some context only when MyFunction[something] is evaluated. This is not the case.
$Context and $ContextPath only affect how source code is parsed (not how expressions are evaluated). In other words, they only affect how the text you write in the package file is interpreted and converted into in-memory expressions. Once the package has been loaded with Get, this interpretation has already happened. MyFunction has been interpreted as the symbol CustomPackage`MyFunction and abc has been interpreted as CustomPackage`Private`abc, according to the value of $Context and $ContextPath at the time each was read. These are the full names of these symbols and this is how they exist in memory.
Load the package and try this:
Block[{$ContextPath},
Print@Definition[MyFunction]
]
You'll see the following printed:
CustomPackage`MyFunction[CustomPackage`Private`arg1_] :=
CustomPackage`Private`arg1+CustomPackage`Private`abc
As you can see, a context is always associated with every symbol.
$endgroup$
So how does
MyFunctionknow the value ofabcat the delayed function call (when it is called) if thePrivate`context isn't on the$ContextPath
There is a misunderstanding here. You are assuming that abc is searched for in some context only when MyFunction[something] is evaluated. This is not the case.
$Context and $ContextPath only affect how source code is parsed (not how expressions are evaluated). In other words, they only affect how the text you write in the package file is interpreted and converted into in-memory expressions. Once the package has been loaded with Get, this interpretation has already happened. MyFunction has been interpreted as the symbol CustomPackage`MyFunction and abc has been interpreted as CustomPackage`Private`abc, according to the value of $Context and $ContextPath at the time each was read. These are the full names of these symbols and this is how they exist in memory.
Load the package and try this:
Block[{$ContextPath},
Print@Definition[MyFunction]
]
You'll see the following printed:
CustomPackage`MyFunction[CustomPackage`Private`arg1_] :=
CustomPackage`Private`arg1+CustomPackage`Private`abc
As you can see, a context is always associated with every symbol.
edited 2 hours ago
answered 2 hours ago
SzabolcsSzabolcs
164k14448946
164k14448946
add a comment |
add a comment |
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