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Minkowski space


Poincare group vs Galilean groupMinkowski MetricConservation of phase space volume in Rindler space-timeMinkowski Metric SignatureMinkowski metric — why does it follow from the constancy of the speed of light?Space-like pion electromagnetic form factorMinkowski metric: Why does it look like it does?Understanding space-like hyperplanes in Minkowski spaceCan an a distance in Minkowski space, based on a Euclidean plane, be time-like?How to Construct Proper Spherical Coordinates in Minkowski Spacetime?













1












$begingroup$


In Minkowski space, coordinates which satisfy



x2=t2-X2>0



Region of space time is time-like.
If its.



x2=t2-X2<0



Region is space-like.
But if



x2=t2-X2=0



` then its "trajectory of light like particles".



I have understood the first two points about time and space like region but I could not get the third one about "light like particles".
My confusion is about why just light like particles? there are many other particles at quantum level.










share|cite|improve this question







New contributor




sk9298 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$

















    1












    $begingroup$


    In Minkowski space, coordinates which satisfy



    x2=t2-X2>0



    Region of space time is time-like.
    If its.



    x2=t2-X2<0



    Region is space-like.
    But if



    x2=t2-X2=0



    ` then its "trajectory of light like particles".



    I have understood the first two points about time and space like region but I could not get the third one about "light like particles".
    My confusion is about why just light like particles? there are many other particles at quantum level.










    share|cite|improve this question







    New contributor




    sk9298 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$















      1












      1








      1





      $begingroup$


      In Minkowski space, coordinates which satisfy



      x2=t2-X2>0



      Region of space time is time-like.
      If its.



      x2=t2-X2<0



      Region is space-like.
      But if



      x2=t2-X2=0



      ` then its "trajectory of light like particles".



      I have understood the first two points about time and space like region but I could not get the third one about "light like particles".
      My confusion is about why just light like particles? there are many other particles at quantum level.










      share|cite|improve this question







      New contributor




      sk9298 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      In Minkowski space, coordinates which satisfy



      x2=t2-X2>0



      Region of space time is time-like.
      If its.



      x2=t2-X2<0



      Region is space-like.
      But if



      x2=t2-X2=0



      ` then its "trajectory of light like particles".



      I have understood the first two points about time and space like region but I could not get the third one about "light like particles".
      My confusion is about why just light like particles? there are many other particles at quantum level.







      quantum-field-theory special-relativity






      share|cite|improve this question







      New contributor




      sk9298 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|cite|improve this question







      New contributor




      sk9298 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|cite|improve this question




      share|cite|improve this question






      New contributor




      sk9298 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      asked 27 mins ago









      sk9298sk9298

      595




      595




      New contributor




      sk9298 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      New contributor





      sk9298 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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          2 Answers
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          2












          $begingroup$


          My confusion is about why just light like particles? there are many other particles at quantum level.




          You are correct. The terminology is historical in nature. Light was the first massless particle to be discovered. The terminology “lightlike” was established before any other massless particles were discovered. Once other massless particles were discovered it was shown that they also travel along lightlike geodesics, but by then the term “lightlike” was well established.



          An alternative term with the same meaning as “lightlike” is “null”. If you prefer then you can always use “null” and just understand that people saying “lightlike” mean the same thing.






          share|cite|improve this answer









          $endgroup$





















            1












            $begingroup$

            Only particles with zero mass can travel between two events which are separated by a light-like distance. The trajectory is called light-like because photons (light) are massless, and historically the first example of a massless particle, as well as the only example in the 1910's. There are other massless particles, like gluons which would also be able to travel between two events separated by a light-like distance.



            The reason why only massless particles are able to travel between two events separated by a light-like distance is that it requires you to travel at exactly the speed of light. You can see this by considering the equation $t^2-x^2=0$, this means that $x=pm t$. These equations are with the units such that the speed of light $c=1$. Thus the particle taking this trajectory is travelling at the speed of light.






            share|cite|improve this answer









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              2 Answers
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              active

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              2 Answers
              2






              active

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              active

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              active

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              2












              $begingroup$


              My confusion is about why just light like particles? there are many other particles at quantum level.




              You are correct. The terminology is historical in nature. Light was the first massless particle to be discovered. The terminology “lightlike” was established before any other massless particles were discovered. Once other massless particles were discovered it was shown that they also travel along lightlike geodesics, but by then the term “lightlike” was well established.



              An alternative term with the same meaning as “lightlike” is “null”. If you prefer then you can always use “null” and just understand that people saying “lightlike” mean the same thing.






              share|cite|improve this answer









              $endgroup$


















                2












                $begingroup$


                My confusion is about why just light like particles? there are many other particles at quantum level.




                You are correct. The terminology is historical in nature. Light was the first massless particle to be discovered. The terminology “lightlike” was established before any other massless particles were discovered. Once other massless particles were discovered it was shown that they also travel along lightlike geodesics, but by then the term “lightlike” was well established.



                An alternative term with the same meaning as “lightlike” is “null”. If you prefer then you can always use “null” and just understand that people saying “lightlike” mean the same thing.






                share|cite|improve this answer









                $endgroup$
















                  2












                  2








                  2





                  $begingroup$


                  My confusion is about why just light like particles? there are many other particles at quantum level.




                  You are correct. The terminology is historical in nature. Light was the first massless particle to be discovered. The terminology “lightlike” was established before any other massless particles were discovered. Once other massless particles were discovered it was shown that they also travel along lightlike geodesics, but by then the term “lightlike” was well established.



                  An alternative term with the same meaning as “lightlike” is “null”. If you prefer then you can always use “null” and just understand that people saying “lightlike” mean the same thing.






                  share|cite|improve this answer









                  $endgroup$




                  My confusion is about why just light like particles? there are many other particles at quantum level.




                  You are correct. The terminology is historical in nature. Light was the first massless particle to be discovered. The terminology “lightlike” was established before any other massless particles were discovered. Once other massless particles were discovered it was shown that they also travel along lightlike geodesics, but by then the term “lightlike” was well established.



                  An alternative term with the same meaning as “lightlike” is “null”. If you prefer then you can always use “null” and just understand that people saying “lightlike” mean the same thing.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered 17 mins ago









                  DaleDale

                  6,5871829




                  6,5871829























                      1












                      $begingroup$

                      Only particles with zero mass can travel between two events which are separated by a light-like distance. The trajectory is called light-like because photons (light) are massless, and historically the first example of a massless particle, as well as the only example in the 1910's. There are other massless particles, like gluons which would also be able to travel between two events separated by a light-like distance.



                      The reason why only massless particles are able to travel between two events separated by a light-like distance is that it requires you to travel at exactly the speed of light. You can see this by considering the equation $t^2-x^2=0$, this means that $x=pm t$. These equations are with the units such that the speed of light $c=1$. Thus the particle taking this trajectory is travelling at the speed of light.






                      share|cite|improve this answer









                      $endgroup$


















                        1












                        $begingroup$

                        Only particles with zero mass can travel between two events which are separated by a light-like distance. The trajectory is called light-like because photons (light) are massless, and historically the first example of a massless particle, as well as the only example in the 1910's. There are other massless particles, like gluons which would also be able to travel between two events separated by a light-like distance.



                        The reason why only massless particles are able to travel between two events separated by a light-like distance is that it requires you to travel at exactly the speed of light. You can see this by considering the equation $t^2-x^2=0$, this means that $x=pm t$. These equations are with the units such that the speed of light $c=1$. Thus the particle taking this trajectory is travelling at the speed of light.






                        share|cite|improve this answer









                        $endgroup$
















                          1












                          1








                          1





                          $begingroup$

                          Only particles with zero mass can travel between two events which are separated by a light-like distance. The trajectory is called light-like because photons (light) are massless, and historically the first example of a massless particle, as well as the only example in the 1910's. There are other massless particles, like gluons which would also be able to travel between two events separated by a light-like distance.



                          The reason why only massless particles are able to travel between two events separated by a light-like distance is that it requires you to travel at exactly the speed of light. You can see this by considering the equation $t^2-x^2=0$, this means that $x=pm t$. These equations are with the units such that the speed of light $c=1$. Thus the particle taking this trajectory is travelling at the speed of light.






                          share|cite|improve this answer









                          $endgroup$



                          Only particles with zero mass can travel between two events which are separated by a light-like distance. The trajectory is called light-like because photons (light) are massless, and historically the first example of a massless particle, as well as the only example in the 1910's. There are other massless particles, like gluons which would also be able to travel between two events separated by a light-like distance.



                          The reason why only massless particles are able to travel between two events separated by a light-like distance is that it requires you to travel at exactly the speed of light. You can see this by considering the equation $t^2-x^2=0$, this means that $x=pm t$. These equations are with the units such that the speed of light $c=1$. Thus the particle taking this trajectory is travelling at the speed of light.







                          share|cite|improve this answer












                          share|cite|improve this answer



                          share|cite|improve this answer










                          answered 20 mins ago









                          LucashWindowWasherLucashWindowWasher

                          30310




                          30310






















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