How to align text above triangle figure Announcing the arrival of Valued Associate #679: Cesar...

At the end of Thor: Ragnarok why don't the Asgardians turn and head for the Bifrost as per their original plan?

In predicate logic, does existential quantification (∃) include universal quantification (∀), i.e. can 'some' imply 'all'?

Using audio cues to encourage good posture

Why is "Consequences inflicted." not a sentence?

How discoverable are IPv6 addresses and AAAA names by potential attackers?

How widely used is the term Treppenwitz? Is it something that most Germans know?

Should I discuss the type of campaign with my players?

What would be the ideal power source for a cybernetic eye?

Can a USB port passively 'listen only'?

2001: A Space Odyssey's use of the song "Daisy Bell" (Bicycle Built for Two); life imitates art or vice-versa?

Why was the term "discrete" used in discrete logarithm?

What's the purpose of writing one's academic biography in the third person?

How to call a function with default parameter through a pointer to function that is the return of another function?

Use BFD on a Virtual-Template Interface

How does the particle を relate to the verb 行く in the structure「A を + B に行く」?

Coloring maths inside a tcolorbox

Why didn't this character "real die" when they blew their stack out in Altered Carbon?

How to react to hostile behavior from a senior developer?

Resolving to minmaj7

What is the role of the transistor and diode in a soft start circuit?

Overriding an object in memory with placement new

Align equal signs while including text over equalities

How come Sam didn't become Lord of Horn Hill?

Short Story with Cinderella as a Voo-doo Witch



How to align text above triangle figure



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Rotate a node but not its content: the case of the ellipse decorationHow to define the default vertical distance between nodes?TikZ scaling graphic and adjust node position and keep font sizealign text in tikz figureNumerical conditional within tikz keys?Relating tree nodes in forest to content in a tableTikZ: Node position in draw environmentLatex and Game Theory: Combining an Extensive and Normal Form for a Three Players GameDrawing graph with Tikz: Link it with main text without overlapping with textTikZ: define arrow starting position based on style and format node label












1















I managed to align my hypotenuse text with the hypotenuse side of my triangle, but I feel like it was done inefficiently using a lot of ~~~~~~ in this line node[above] {$sqrt{1+x^2}$~~~~~~~} (B) --.



Is there a better way to get the same alignment that I have now without the excessive use of ~?



enter image description here



documentclass[hidelinks,14pt, letterpaper]{extarticle}
usepackage{amsmath, amssymb, tikz}

newcommand{pythagwidth}{3cm}
newcommand{pythagheight}{2cm}

begin{document}
begin{figure}[h]
centering

begin{tikzpicture}[scale=1.25]
coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
draw
(A) --
node[above] {$sqrt{1+x^2}$~~~~~~~} (B) --
node[right] {?} (C) --
node[below] {?}
(A);
draw
(1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);

end{tikzpicture}
caption{Caption}
label{fig:my_label}
end{figure}
end{document}









share|improve this question



























    1















    I managed to align my hypotenuse text with the hypotenuse side of my triangle, but I feel like it was done inefficiently using a lot of ~~~~~~ in this line node[above] {$sqrt{1+x^2}$~~~~~~~} (B) --.



    Is there a better way to get the same alignment that I have now without the excessive use of ~?



    enter image description here



    documentclass[hidelinks,14pt, letterpaper]{extarticle}
    usepackage{amsmath, amssymb, tikz}

    newcommand{pythagwidth}{3cm}
    newcommand{pythagheight}{2cm}

    begin{document}
    begin{figure}[h]
    centering

    begin{tikzpicture}[scale=1.25]
    coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
    coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
    coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
    draw
    (A) --
    node[above] {$sqrt{1+x^2}$~~~~~~~} (B) --
    node[right] {?} (C) --
    node[below] {?}
    (A);
    draw
    (1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);

    end{tikzpicture}
    caption{Caption}
    label{fig:my_label}
    end{figure}
    end{document}









    share|improve this question

























      1












      1








      1








      I managed to align my hypotenuse text with the hypotenuse side of my triangle, but I feel like it was done inefficiently using a lot of ~~~~~~ in this line node[above] {$sqrt{1+x^2}$~~~~~~~} (B) --.



      Is there a better way to get the same alignment that I have now without the excessive use of ~?



      enter image description here



      documentclass[hidelinks,14pt, letterpaper]{extarticle}
      usepackage{amsmath, amssymb, tikz}

      newcommand{pythagwidth}{3cm}
      newcommand{pythagheight}{2cm}

      begin{document}
      begin{figure}[h]
      centering

      begin{tikzpicture}[scale=1.25]
      coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
      coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
      coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
      draw
      (A) --
      node[above] {$sqrt{1+x^2}$~~~~~~~} (B) --
      node[right] {?} (C) --
      node[below] {?}
      (A);
      draw
      (1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);

      end{tikzpicture}
      caption{Caption}
      label{fig:my_label}
      end{figure}
      end{document}









      share|improve this question














      I managed to align my hypotenuse text with the hypotenuse side of my triangle, but I feel like it was done inefficiently using a lot of ~~~~~~ in this line node[above] {$sqrt{1+x^2}$~~~~~~~} (B) --.



      Is there a better way to get the same alignment that I have now without the excessive use of ~?



      enter image description here



      documentclass[hidelinks,14pt, letterpaper]{extarticle}
      usepackage{amsmath, amssymb, tikz}

      newcommand{pythagwidth}{3cm}
      newcommand{pythagheight}{2cm}

      begin{document}
      begin{figure}[h]
      centering

      begin{tikzpicture}[scale=1.25]
      coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
      coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
      coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
      draw
      (A) --
      node[above] {$sqrt{1+x^2}$~~~~~~~} (B) --
      node[right] {?} (C) --
      node[below] {?}
      (A);
      draw
      (1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);

      end{tikzpicture}
      caption{Caption}
      label{fig:my_label}
      end{figure}
      end{document}






      tikz-pgf






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 1 hour ago









      Evan KimEvan Kim

      1453




      1453






















          2 Answers
          2






          active

          oldest

          votes


















          3














          Something like this? I use node[midway,above left=0pt,inner sep=0.5pt] {$sqrt{1+x^2}$}, where inner sep=0.5pt controls the distance.



          documentclass[hidelinks,14pt, letterpaper]{extarticle}
          usepackage{amsmath, amssymb, tikz}

          newcommand{pythagwidth}{3cm}
          newcommand{pythagheight}{2cm}

          begin{document}
          begin{figure}[h]
          centering

          begin{tikzpicture}[scale=1.25]
          coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
          coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
          coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
          draw
          (A) --
          node[midway,above left=0pt,inner sep=0.5pt] {$sqrt{1+x^2}$} (B) --
          node[right] {?} (C) --
          node[below] {?}
          (A);
          draw
          (1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);

          end{tikzpicture}
          caption{Caption}
          label{fig:my_label}
          end{figure}
          end{document}


          enter image description here



          ADDENDUM: Just for fun: an even simpler and shorter code with TikZ...



          documentclass[tikz,border=3.14mm]{standalone}
          begin{document}
          begin{tikzpicture}[scale=1.25]
          draw (-1.5,-1) coordinate [label=left:$A$] (A) --
          node[midway,above,sloped] {$sqrt{1+x^2}$}
          (1.5,1) coordinate [label=above:$B$] (B) --
          node[right] {?}
          (1.5,-1)coordinate [label=below right:$C$] (C) --
          node[below] {?} cycle;
          draw ([xshift=-0.25cm]C) |- ([yshift=0.25cm]C);
          end{tikzpicture}
          end{document}


          enter image description here






          share|improve this answer


























          • yes that is it thanks! It seems like simply having node [midway,above left=0pt] {$sqrt{1+x^2}$} (B) -- does the trick too without using inner_sept

            – Evan Kim
            1 hour ago





















          1














          Just for fun: with pstricks, a very short code to have this figure:



           documentclass{article}
          usepackage{pst-eucl}%,
          usepackage{auto-pst-pdf}

          begin{document}

          begin{postscript}
          psset{unit=2, linejoin=1, PointSymbol=none,}
          pstTriangle(-1.5,-1){A}(1.5,1){B}(1.5,-1){C}
          ncline[linestyle=none]{A}{B}naput*[nrot=:U]{$ sqrt{1 + x^2}$}
          psset{PointName=none}
          pstMiddleAB{A}{C}{I}uput[d](I){?}
          pstMiddleAB{B}{C}{J}uput[r](J){?}
          end{postscript}

          end{document}


          enter image description here






          share|improve this answer
























            Your Answer








            StackExchange.ready(function() {
            var channelOptions = {
            tags: "".split(" "),
            id: "85"
            };
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function() {
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled) {
            StackExchange.using("snippets", function() {
            createEditor();
            });
            }
            else {
            createEditor();
            }
            });

            function createEditor() {
            StackExchange.prepareEditor({
            heartbeatType: 'answer',
            autoActivateHeartbeat: false,
            convertImagesToLinks: false,
            noModals: true,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: null,
            bindNavPrevention: true,
            postfix: "",
            imageUploader: {
            brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
            contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
            allowUrls: true
            },
            onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            });


            }
            });














            draft saved

            draft discarded


















            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f485211%2fhow-to-align-text-above-triangle-figure%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown

























            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            3














            Something like this? I use node[midway,above left=0pt,inner sep=0.5pt] {$sqrt{1+x^2}$}, where inner sep=0.5pt controls the distance.



            documentclass[hidelinks,14pt, letterpaper]{extarticle}
            usepackage{amsmath, amssymb, tikz}

            newcommand{pythagwidth}{3cm}
            newcommand{pythagheight}{2cm}

            begin{document}
            begin{figure}[h]
            centering

            begin{tikzpicture}[scale=1.25]
            coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
            coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
            coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
            draw
            (A) --
            node[midway,above left=0pt,inner sep=0.5pt] {$sqrt{1+x^2}$} (B) --
            node[right] {?} (C) --
            node[below] {?}
            (A);
            draw
            (1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);

            end{tikzpicture}
            caption{Caption}
            label{fig:my_label}
            end{figure}
            end{document}


            enter image description here



            ADDENDUM: Just for fun: an even simpler and shorter code with TikZ...



            documentclass[tikz,border=3.14mm]{standalone}
            begin{document}
            begin{tikzpicture}[scale=1.25]
            draw (-1.5,-1) coordinate [label=left:$A$] (A) --
            node[midway,above,sloped] {$sqrt{1+x^2}$}
            (1.5,1) coordinate [label=above:$B$] (B) --
            node[right] {?}
            (1.5,-1)coordinate [label=below right:$C$] (C) --
            node[below] {?} cycle;
            draw ([xshift=-0.25cm]C) |- ([yshift=0.25cm]C);
            end{tikzpicture}
            end{document}


            enter image description here






            share|improve this answer


























            • yes that is it thanks! It seems like simply having node [midway,above left=0pt] {$sqrt{1+x^2}$} (B) -- does the trick too without using inner_sept

              – Evan Kim
              1 hour ago


















            3














            Something like this? I use node[midway,above left=0pt,inner sep=0.5pt] {$sqrt{1+x^2}$}, where inner sep=0.5pt controls the distance.



            documentclass[hidelinks,14pt, letterpaper]{extarticle}
            usepackage{amsmath, amssymb, tikz}

            newcommand{pythagwidth}{3cm}
            newcommand{pythagheight}{2cm}

            begin{document}
            begin{figure}[h]
            centering

            begin{tikzpicture}[scale=1.25]
            coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
            coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
            coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
            draw
            (A) --
            node[midway,above left=0pt,inner sep=0.5pt] {$sqrt{1+x^2}$} (B) --
            node[right] {?} (C) --
            node[below] {?}
            (A);
            draw
            (1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);

            end{tikzpicture}
            caption{Caption}
            label{fig:my_label}
            end{figure}
            end{document}


            enter image description here



            ADDENDUM: Just for fun: an even simpler and shorter code with TikZ...



            documentclass[tikz,border=3.14mm]{standalone}
            begin{document}
            begin{tikzpicture}[scale=1.25]
            draw (-1.5,-1) coordinate [label=left:$A$] (A) --
            node[midway,above,sloped] {$sqrt{1+x^2}$}
            (1.5,1) coordinate [label=above:$B$] (B) --
            node[right] {?}
            (1.5,-1)coordinate [label=below right:$C$] (C) --
            node[below] {?} cycle;
            draw ([xshift=-0.25cm]C) |- ([yshift=0.25cm]C);
            end{tikzpicture}
            end{document}


            enter image description here






            share|improve this answer


























            • yes that is it thanks! It seems like simply having node [midway,above left=0pt] {$sqrt{1+x^2}$} (B) -- does the trick too without using inner_sept

              – Evan Kim
              1 hour ago
















            3












            3








            3







            Something like this? I use node[midway,above left=0pt,inner sep=0.5pt] {$sqrt{1+x^2}$}, where inner sep=0.5pt controls the distance.



            documentclass[hidelinks,14pt, letterpaper]{extarticle}
            usepackage{amsmath, amssymb, tikz}

            newcommand{pythagwidth}{3cm}
            newcommand{pythagheight}{2cm}

            begin{document}
            begin{figure}[h]
            centering

            begin{tikzpicture}[scale=1.25]
            coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
            coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
            coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
            draw
            (A) --
            node[midway,above left=0pt,inner sep=0.5pt] {$sqrt{1+x^2}$} (B) --
            node[right] {?} (C) --
            node[below] {?}
            (A);
            draw
            (1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);

            end{tikzpicture}
            caption{Caption}
            label{fig:my_label}
            end{figure}
            end{document}


            enter image description here



            ADDENDUM: Just for fun: an even simpler and shorter code with TikZ...



            documentclass[tikz,border=3.14mm]{standalone}
            begin{document}
            begin{tikzpicture}[scale=1.25]
            draw (-1.5,-1) coordinate [label=left:$A$] (A) --
            node[midway,above,sloped] {$sqrt{1+x^2}$}
            (1.5,1) coordinate [label=above:$B$] (B) --
            node[right] {?}
            (1.5,-1)coordinate [label=below right:$C$] (C) --
            node[below] {?} cycle;
            draw ([xshift=-0.25cm]C) |- ([yshift=0.25cm]C);
            end{tikzpicture}
            end{document}


            enter image description here






            share|improve this answer















            Something like this? I use node[midway,above left=0pt,inner sep=0.5pt] {$sqrt{1+x^2}$}, where inner sep=0.5pt controls the distance.



            documentclass[hidelinks,14pt, letterpaper]{extarticle}
            usepackage{amsmath, amssymb, tikz}

            newcommand{pythagwidth}{3cm}
            newcommand{pythagheight}{2cm}

            begin{document}
            begin{figure}[h]
            centering

            begin{tikzpicture}[scale=1.25]
            coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
            coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
            coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
            draw
            (A) --
            node[midway,above left=0pt,inner sep=0.5pt] {$sqrt{1+x^2}$} (B) --
            node[right] {?} (C) --
            node[below] {?}
            (A);
            draw
            (1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);

            end{tikzpicture}
            caption{Caption}
            label{fig:my_label}
            end{figure}
            end{document}


            enter image description here



            ADDENDUM: Just for fun: an even simpler and shorter code with TikZ...



            documentclass[tikz,border=3.14mm]{standalone}
            begin{document}
            begin{tikzpicture}[scale=1.25]
            draw (-1.5,-1) coordinate [label=left:$A$] (A) --
            node[midway,above,sloped] {$sqrt{1+x^2}$}
            (1.5,1) coordinate [label=above:$B$] (B) --
            node[right] {?}
            (1.5,-1)coordinate [label=below right:$C$] (C) --
            node[below] {?} cycle;
            draw ([xshift=-0.25cm]C) |- ([yshift=0.25cm]C);
            end{tikzpicture}
            end{document}


            enter image description here







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 28 mins ago

























            answered 1 hour ago









            marmotmarmot

            118k6153288




            118k6153288













            • yes that is it thanks! It seems like simply having node [midway,above left=0pt] {$sqrt{1+x^2}$} (B) -- does the trick too without using inner_sept

              – Evan Kim
              1 hour ago





















            • yes that is it thanks! It seems like simply having node [midway,above left=0pt] {$sqrt{1+x^2}$} (B) -- does the trick too without using inner_sept

              – Evan Kim
              1 hour ago



















            yes that is it thanks! It seems like simply having node [midway,above left=0pt] {$sqrt{1+x^2}$} (B) -- does the trick too without using inner_sept

            – Evan Kim
            1 hour ago







            yes that is it thanks! It seems like simply having node [midway,above left=0pt] {$sqrt{1+x^2}$} (B) -- does the trick too without using inner_sept

            – Evan Kim
            1 hour ago













            1














            Just for fun: with pstricks, a very short code to have this figure:



             documentclass{article}
            usepackage{pst-eucl}%,
            usepackage{auto-pst-pdf}

            begin{document}

            begin{postscript}
            psset{unit=2, linejoin=1, PointSymbol=none,}
            pstTriangle(-1.5,-1){A}(1.5,1){B}(1.5,-1){C}
            ncline[linestyle=none]{A}{B}naput*[nrot=:U]{$ sqrt{1 + x^2}$}
            psset{PointName=none}
            pstMiddleAB{A}{C}{I}uput[d](I){?}
            pstMiddleAB{B}{C}{J}uput[r](J){?}
            end{postscript}

            end{document}


            enter image description here






            share|improve this answer




























              1














              Just for fun: with pstricks, a very short code to have this figure:



               documentclass{article}
              usepackage{pst-eucl}%,
              usepackage{auto-pst-pdf}

              begin{document}

              begin{postscript}
              psset{unit=2, linejoin=1, PointSymbol=none,}
              pstTriangle(-1.5,-1){A}(1.5,1){B}(1.5,-1){C}
              ncline[linestyle=none]{A}{B}naput*[nrot=:U]{$ sqrt{1 + x^2}$}
              psset{PointName=none}
              pstMiddleAB{A}{C}{I}uput[d](I){?}
              pstMiddleAB{B}{C}{J}uput[r](J){?}
              end{postscript}

              end{document}


              enter image description here






              share|improve this answer


























                1












                1








                1







                Just for fun: with pstricks, a very short code to have this figure:



                 documentclass{article}
                usepackage{pst-eucl}%,
                usepackage{auto-pst-pdf}

                begin{document}

                begin{postscript}
                psset{unit=2, linejoin=1, PointSymbol=none,}
                pstTriangle(-1.5,-1){A}(1.5,1){B}(1.5,-1){C}
                ncline[linestyle=none]{A}{B}naput*[nrot=:U]{$ sqrt{1 + x^2}$}
                psset{PointName=none}
                pstMiddleAB{A}{C}{I}uput[d](I){?}
                pstMiddleAB{B}{C}{J}uput[r](J){?}
                end{postscript}

                end{document}


                enter image description here






                share|improve this answer













                Just for fun: with pstricks, a very short code to have this figure:



                 documentclass{article}
                usepackage{pst-eucl}%,
                usepackage{auto-pst-pdf}

                begin{document}

                begin{postscript}
                psset{unit=2, linejoin=1, PointSymbol=none,}
                pstTriangle(-1.5,-1){A}(1.5,1){B}(1.5,-1){C}
                ncline[linestyle=none]{A}{B}naput*[nrot=:U]{$ sqrt{1 + x^2}$}
                psset{PointName=none}
                pstMiddleAB{A}{C}{I}uput[d](I){?}
                pstMiddleAB{B}{C}{J}uput[r](J){?}
                end{postscript}

                end{document}


                enter image description here







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 49 mins ago









                BernardBernard

                176k778210




                176k778210






























                    draft saved

                    draft discarded




















































                    Thanks for contributing an answer to TeX - LaTeX Stack Exchange!


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid



                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.


                    To learn more, see our tips on writing great answers.




                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function () {
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f485211%2fhow-to-align-text-above-triangle-figure%23new-answer', 'question_page');
                    }
                    );

                    Post as a guest















                    Required, but never shown





















































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown

































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown







                    Popular posts from this blog

                    迭戈·戈丁...

                    A phrase ”follow into" in a context The 2019 Stack Overflow Developer Survey Results Are...

                    1960s short story making fun of James Bond-style spy fiction The 2019 Stack Overflow Developer...